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Thepotemich [5.8K]
3 years ago
10

Find the sum. r/r^2-q^2 + 5/r+q​

Mathematics
1 answer:
pickupchik [31]3 years ago
7 0

Answer:

The answer is:  

\frac{6r-5q}{r^2-q^2}

which agrees with the last answer option (D) in the list.

Step-by-step explanation:

In order to add rational expressions, we need to express them with the same denominator. Therefore we examine what factors there are in the first denominator, which happens to be a difference of squares which is readily factored out as:

r^2-q^2=(r+q)\,(r-q)

the second denominator consists of only one of these factors: (r+q), then in order to express both rational expressions with the same common denominator, we multiply numerator and denominator of the second fraction by the factor: (r-q)

Then we get two expressions that can be easily added as shown below:

\frac{r}{(r+q)\,(r-q)} +\frac{5\,(r-q)}{(r+q)\,(r-q)} =\frac{r+5(r-q)}{(r+q)(r-q)} =\frac{r+5r-5q}{(r+q)\,(r-q)} =\frac{6r-5q}{r^2-q^2}

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