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Keith_Richards [23]
4 years ago
10

Josie and Tyler play the following game. an integer between 0 and 799 inclusive is selected and given to josie. whenever josie r

eceives a number, she quadruples it and passes the result to tyler. whenever tyler receives a number he adds 25 to it and passes it to josie. the winner is the last person who produces a number less than 800. what is smallest initial number that results in a win for josie?
Mathematics
1 answer:
aleksley [76]4 years ago
4 0

Answer:

what grade you in

Step-by-step explanation:

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The morning temperature was at 23.5° F. Later that evening the temperature had dropped to 15.6° F. What was the change in temper
salantis [7]

Answer:

Jake's answer is true; the change in temperature is -7.9° F.

Step-by-step explanation:

The change in temperature is the final value minus the initial value. Evening minus the morning.

The final value is 15.6° F, the initial value is 23.5° F.

So 15.6 - 23.5 = -7.9

Jake's answer is true.

3 0
3 years ago
How do write 841, 620 in three different ways?
lesya [120]

Answer:

1) 841,620

2) 800,000+40,000+1,000+600+20

3) Eight hundred forty-one thousand, six hundred twenty

Hope this helps!

5 0
3 years ago
A circle is inscribed in a square. Write and simplify an expression for the ratio of the area of the square to the area of the c
irina [24]
Given:
circle inscribed in a square.
Side length of the square = diameter of the circle.
Let x side length and diameter.

Area of a square = x²

Area of a circle = πr²

r = radius ; half of the diameter. = x/2

Area of a circle = π * (x/2)²  or π (x²/4)

Ratio of the area of the square to the area of the circle

x² : π(x²/4)   or x² / πx²/4

x² * 4/πx² = 4/π
5 0
3 years ago
Read 2 more answers
Solve the above que no. 55
aleksandr82 [10.1K]

Answer:

Let \left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right), we proceed to prove the trigonometric expression by trigonometric identity:

1) \left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right) Given

2) \left(1+\frac{\cos^{2}A}{\sin^{2}A} \right)\cdot \left(1+\frac{\sin^{2}A}{\cos^{2}A} \right)   \tan A = \frac{1}{\cot A} = \frac{\sin A}{\cos A}

3) \left(\frac{\sin^{2}A+\cos^{2}A}{\sin^{2}A} \right)\cdot \left(\frac{\cos^{2}A+\sin^{2}A}{\cos^{2}A} \right)    

4) \left(\frac{1}{\sin^{2}A} \right)\cdot \left(\frac{1}{\cos^{2}A} \right)    \sin^{2}A+\cos^{2}A = 1

5) \frac{1}{\sin^{2}A\cdot \cos^{2}A}

6) \frac{1}{\sin^{2}A\cdot (1-\sin^{2}A)}    \sin^{2}A+\cos^{2}A = 1

7) \frac{1}{\sin^{2}A-\sin^{4}A} Result

Step-by-step explanation:

Let \left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right), we proceed to prove the trigonometric expression by trigonometric identity:

1) \left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right) Given

2) \left(1+\frac{\cos^{2}A}{\sin^{2}A} \right)\cdot \left(1+\frac{\sin^{2}A}{\cos^{2}A} \right)   \tan A = \frac{1}{\cot A} = \frac{\sin A}{\cos A}

3) \left(\frac{\sin^{2}A+\cos^{2}A}{\sin^{2}A} \right)\cdot \left(\frac{\cos^{2}A+\sin^{2}A}{\cos^{2}A} \right)    

4) \left(\frac{1}{\sin^{2}A} \right)\cdot \left(\frac{1}{\cos^{2}A} \right)    \sin^{2}A+\cos^{2}A = 1

5) \frac{1}{\sin^{2}A\cdot \cos^{2}A}

6) \frac{1}{\sin^{2}A\cdot (1-\sin^{2}A)}    \sin^{2}A+\cos^{2}A = 1

7) \frac{1}{\sin^{2}A-\sin^{4}A} Result

4 0
3 years ago
Over 30 points please help me i need it bad
pashok25 [27]
Distance formula: d= square root of (x2-x1)^2+(y2-y1)^2
(3,5) (7,3)
d= square root of (7-3)^2+(3-5)^2
d= square root of (4^2)+(-2^2)
d= square root of 16+4
d= square root of 20
d=4.47...rounded= 4.5
Hope this helped!
6 0
3 years ago
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