Tan 2x - cot x = 0
2tan x / (1 - tan^2 x) - 1/tan x = 0
2tan^2 x - (1 - tan^2 x) = 0
2tan^2 x - 1 + tan^2 x = 0
3tan^2 x - 1 = 0
tan^2 x = 1/3
tan x = + or - 1/√3
Answer:

Step-by-step explanation:
By logarithm rules

Answer:
Here are some answers
1. If you meant 6x = 0 then your answer is 0
2. If you meant 6 + x = 0 then your answer is -6
Step-by-step explanation:
Use exponent property of logs.
logb(x²) = 2 logb(x) = 2(0.49) = 0.98
-7 - 12 = -1(7 + 12) = -1(19) = -19
Your answer is A.