Can someone help me pls

Mathematics

2 answers:

Alisiya [41]3 years ago

8 0

Answer:

c. 14q²-2q+14/3

Step-by-step explanation:

9q²-2/3(3q-7)+5q²

multiply 2/3 with bracket

= 9q²-2q+14/3+5q²

=14q²-2q+14/3

Mamont248 [21]3 years ago

3 0

Answer:

Step-by-step explanation:

Given

9q² - $\frac{2}{3}$ (3q - 7) + 5q² ← distribute parenthesis by - $\frac{2}{3}$

= 9q² - 2q + $\frac{14}{3}$ + 5q² ← collect like terms

= 14q² - 2q + $\frac{14}{3}$ → C

You might be interested in

Finals are over, and you are moving back home for the summer. You need to rent a truck to move your possessions from the colleg

rewona [7]

In short you just multiply 0.480.48 by the amount of miles you drive add that to 24.9024.90 and you get you total
for example: if you take the first company if you drive 200 miles per day it will cost you 24.9024.90 with an extra 96.096 wich will add up to 120.99849 in total per day

5 0

3 years ago

How can i find the surface area of a rectangle

omeli [17]

Answer:

Legenth times width

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Multiply. (2x2 + 4x - 3)(x2 - 2x + 5)

BigorU [14]

For a moment, let $y=x^2-2x+5$ . Then by the distributive property,

$(2x^2+4x-3)p=2x^2p+4xp-3p$

Again by the distributive property,

$2x^2p=2x^2(x^2-2x+5)=2x^4-4x^3+10x^2$

$4xp=4x(x^2-2x+5)=4x^3-8x^2+20x$

$-3p=-3(x^2-2x+5)=-3x^2+6x-15$

Taking everything together, we get

$(2x^2+4x-3)(x^2-2x+5)=(2x^4-4x^3+10x^2)+(4x^3-8x^2+20x)+(-3x^2+6x-15)$
$(2x^2+4x-3)(x^2-2x+5)=2x^4-x^2+26x-15$