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Minchanka [31]
4 years ago
10

What is the radius and diameter of the following circle? 11 cm

Mathematics
1 answer:
tresset_1 [31]4 years ago
8 0
Answer:
22
Explanation:
The radius of a circle is exactly half the length of the diameter. Thus, to find the diameter when given the radius, multiply the radius's length by
2
.
2
r
=
d
2
×
11
=
d
22
=
d

Hope this helps.
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8 + -8 is zero because of you have 8 then take away 8 then you are left with nothing. -4 plus 6 is basically 6-4 which is 2.
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Read 2 more answers
. When 2 times a number is increased by 4,
Alinara [238K]

Answer: The number is 7

Step-by-step explanation:

Let x be the [number]

<u />

<u>Rephrase the expression</u>

2 times a number is increased by 4, it is the same as 25 decreased by the number

2x+4=25-x

<u>Calculate</u>

Given

2x+4=25-x

Add x on both sides

2x+4+x=25-x+x

3x+4=25

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3x+4-4=25-4

3x=21

Divide 3 on both sides

3x/3=21/3

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Hope this helps!! :)

Please let me know if you have any questions

4 0
3 years ago
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IgorLugansk [536]

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3 0
3 years ago
Let N be the universal set and A, B, C, D be its subsets given by A={x:xisaevennaturalnumber},B={x:xNandxisamultipleof3} C={x:x
Svet_ta [14]

Answer:

A^{'} = {1,3,5,7,9,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = {1,2,3,4,5}

D^{'} = {10,11,12,13,14,15,......}

Step-by-step explanation:

Solution:

It is given that, Universal set is the set of all Natural Numbers.

and

Set A, Set B, Set  C, Set D are subsets of Universal set.

A = {x:x is even natural numbers} = {2,4,6,8,10,.....}

B = {x:x ∈ N and x is a multiple of 3} = {3,6,9,12,15,....}

C = {x:x∈ N and x < 5} = {6,7,8,9,10,.....}

D = {x:x ∈ N and x > 10} = {1,2,3,4,5,6,7,8,9}

U = {1,2,3,4,5,6,7,8,9,10,11,........}

Complements:

A^{'} = U-A = {1,2,3,4,5,6,7,8,9,10,11,........} - {2,4,6,8,10,.....}

A^{'} = {1,3,5,7,9,....}

B^{'} = U-B =  {1,2,3,4,5,6,7,8,9,10,11,........} - {3,6,9,12,15,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = U-C = {1,2,3,4,5,6,7,8,9,10,11,........} - {6,7,8,9,10,.....}

C^{'} = {1,2,3,4,5}

D^{'} = {1,2,3,4,5,6,7,8,9,10,11,........} - {1,2,3,4,5,6,7,8,9}

D^{'} = {10,11,12,13,14,15,......}

8 0
3 years ago
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