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andriy [413]
3 years ago
5

Laraine worked 40 regular hours last week, plus 3 overtime hours at the 1.5 rate. Her pay was $476.15. What was her hourly rate?

Mathematics
1 answer:
Oksanka [162]3 years ago
6 0

Answer:

Her hourly rate is $10.7

Step-by-step explanation:

Here, we are interested in calculating Laraine hourly rate.

In the question, we are told that the overtime rate is 1.5 times the regular hours rate.

Now, let the regular hours rate be $x / hour

For a total of 40 hours, the total money made will be 40 * x = $40x

Now let’s look at the overtime;

Since the overtime is 1.5 times the regular and she had 3 overtime hours;

Money obtained from overtime will be 1.5 * x * 3 = $4.5x

Let’s add this to the regular and equate to the total money made;

4.5x + 40x = 476.15

44.5x = 476.15

x = 476.15/44.5

x = 10.7

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7 0
3 years ago
Fawn plants 2/3 of the garden with vegetables. Her son plants the remainder of the garden. He decides to use 1/2 of his space to
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Drawing it out helps too! Good luck!
4 0
3 years ago
Create a 3rd degree polynomial function with one zero at three. Sketch a graph
DedPeter [7]

Answer:

f(x) =  {x}^{3}  - 9 {x}^{2}  + 27x - 27

Step-by-step explanation:

We want to create a third degree polynomial function with one zero at three.

In other words, we want to find a polynomial function with roots x=3 , multiplicity, 3.

Since x=3 is a solution, x-3 is the only factor that repeats thrice.

f(x) =  {(x - 3)}^{3}

We expand to get:

f(x) =  x( {x}^{2}  - 6x  + 9) - 3( {x}^{2}  - 6x + 9)

f(x) =  {x}^{3}  - 6 {x}^{2}  + 9x- 3 {x}^{2}   + 18x  - 27

This simplifies to:

f(x) =  {x}^{3}  - 9 {x}^{2}  + 27x - 27

See attachment for graph.

4 0
3 years ago
The ratio of a to b is 3 to 1, and the ratio of b to c is 1 to 5. What is the value of 2a+3b/ 4b+3c?
Nostrana [21]

Answer:

B

Step-by-step explanation:

Expressing the ratios as fractions, that is

\frac{a}{b} = \frac{3}{1} ( cross- multiply )

a = 3b

\frac{b}{c} = \frac{1}{5} ( cross- multiply )

c = 5b

------------------------------------------

Given

\frac{2a+3b}{4b+3c} , substitute values from above for a and c

= \frac{2(3b)+3b}{4b+3(5b)}

= \frac{6b+3b}{4b+15b}

= \frac{9b}{19b} ← cancel b on numerator/ denominator

= \frac{9}{19} → B

6 0
3 years ago
Plot these coordinates and determine the resulting figure. (0, 2) (4, 6) (10, 12) (18, 20) A) circle B) curve C) line D) parabol
inna [77]
We have that

<span>A (0, 2) B (4, 6) C (10, 12) D (18, 20)
</span>
using a graph tool
see the attached figure  

the answer is 
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8 0
2 years ago
Read 2 more answers
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