All categories

3 years ago

Find one value of xxx that is a solution to the equation (2x+3) 2 −6x−9=0

Mathematics

1 answer:

vesna_86 [32]3 years ago

3 0

(2x+3) ^2 −6x−9=0

(2x+3) (2x+3) −6x−9=0

Foil

4x^2 +6x+6x+9-6x-9=0

4x^2 +12x+9-6x-9=0

Combine like terms

4x^2 +6x=0

factor out 2x

2x(2x+3)=0

2x=0 2x+3=0

x=0 2x=-3

x=-3/2

Answer x=-3/2, 0

You might be interested in

Wendy scores 24 points in a basketball game. If all of her baskets were 3-point shots, how many baskets did she make?

yarga [219]

Hello!

If all her shots were 3 pointers we will just divide

24÷3=8

Wendy made 8 baskets.

I hope this helps!

5 0

3 years ago

Read 2 more answers

Which number line shows the solution to the inequality -3x - 5 < -2 ?

Inessa05 [86]

The answer to his is A

3 0

3 years ago

Write an equation that could represent the function table

ExtremeBDS [4]

Answer:

y = $x^{2}$

Step-by-step explanation:

Squaring a number means multiplying the number by itself. 0*0=0. 1*1=1. 2*2=4, and 3*3=9. This is the pattern shown in the table.

8 0

2 years ago

Read 2 more answers

Which fraction is equal to 0.7 repeating

svlad2 [7]

Answer:7/9

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Please help me<br> Show your work

GrogVix [38]

<u>ANSWER TO PART A</u>

The given triangle has vertices $J(-4,1), K(-4,-2),L(-3,-1)$

The mapping for rotation through $90\degree$ counterclockwise has the mapping

$(x,y)\rightarrow (-y,x)$

Therefore

$J(-4,1)\rightarrow J'(-1,-4)$

$K(-4,-2)\rightarrow K'(2,-4)$

$L(-3,-1)\rightarrow L'(1,-3)$

We plot all this point and connect them with straight lines.

ANSWER TO PART B

For a reflection across the y-axis we negate the x coordinates.

The mapping is

$(x,y)\rightarrow (-x,y)$

Therefore

$J(-4,1)\rightarrow J''(4,1)$

$K(-4,-2)\rightarrow K''(4,-2)$

$L(-3,-1)\rightarrow L''(3,-1)$

We plot all this point and connect them with straight lines.

See graph in attachment

7 0

3 years ago