If m<1 = m<2, then 3m<1 =????

Solve log(base 2) (x+1) + log (base 2) (x-5)= 4

Afina-wow [57]

(x+1)(x-5)= 2^4=16

x^2 -4x -5 =16

x^2-4x-21=0

x= -3 or 7
but we would choose 7 as the answer as -3 gives negative value at (x+1) and we know that log of negative number is not defined.

6 0

3 years ago

SIMPLIFY 3(4x+4)-4=?

kykrilka [37]

12x+8 is the answer

3 0

2 years ago

Read 2 more answers

An order form from least to greatest with these numbers 2.07,2 an 7/10,2.67 -2.67

olganol [36]

Answer:

Step-by-step explanation:

-2.67

7/10

2.67

2.07,2

4 0

3 years ago

Find the area of a circular pond having radius Ans: 616 m 14 m.

krek1111 [17]

Step-by-step explanation:

Area of circular pond=22/7×14×14

=22/7×196

=616m

3 0

2 years ago

Tacoma's population in 2000 was about 200 thousand, and had been growing by about 9% each year. a. Write a recursive formula for

KIM [24]

Answer:

a) The recurrence formula is $P_n = \frac{109}{100}P_{n-1}$ .

b) The general formula for the population of Tacoma is

$P_n = \left(\frac{109}{100}\right)^nP_{0}$ .

c) In 2016 the approximate population of Tacoma will be 794062 people.

d) The population of Tacoma should exceed the 400000 people by the year 2009.

Step-by-step explanation:

a) We have the population in the year 2000, which is 200 000 people. Let us write $P_0 = 200 000$ . For the population in 2001 we will use $P_1$ , for the population in 2002 we will use $P_2$ , and so on.

In the following year, 2001, the population grow 9% with respect to the previous year. This means that $P_0$ is equal to $P_1$ plus 9% of the population of 2000. Notice that this can be written as

$P_1 = P_0 + (9/100)*P_0 = \left(1-\frac{9}{100}\right)P_0 = \frac{109}{100}P_0$ .

In 2002, we will have the population of 2001, $P_1$ , plus the 9% of $P_1$ . This is

$P_2 = P_1 + (9/100)*P_1 = \left(1-\frac{9}{100}\right)P_1 = \frac{109}{100}P_1$ .

So, it is not difficult to notice that the general recurrence is

$P_n = \frac{109}{100}P_{n-1}$ .

b) In the previous formula we only need to substitute the expression for $P_{n-1}$ :

$P_{n-1} = \frac{109}{100}P_{n-2}$ .

Then,

$P_n = \left(\frac{109}{100}\right)^2P_{n-2}$ .

Repeating the procedure for $P_{n-3}$ we get

$P_n = \left(\frac{109}{100}\right)^3P_{n-3}$ .

But we can do the same operation n times, so

$P_n = \left(\frac{109}{100}\right)^nP_{0}$ .

c) Recall the notation we have used:

$P_{0}$ for 2000, $P_{1}$ for 2001, $P_{2}$ for 2002, and so on. Then, 2016 is $P_{16}$ . So, in order to obtain the approximate population of Tacoma in 2016 is