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kirill [66]
3 years ago
14

Solve for x , 2x-11 -9+ x

Mathematics
1 answer:
romanna [79]3 years ago
3 0
2x - 11
-9 + x
equate the equations
2x - 11 = -9 + x
bring like terms to one side
2x - 11 = -9 + x
- x   +11   +11  - x
-11 and +11 cancels out
+x and -x cancels out
2x - x = 11 - 9
x = 2


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-3/2

Step-by-step explanation:

Slope=rise/run

Pick any 2 points and you can see that for every increase in 2 increases for x, there are 3 decreases for y.

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A car can travel 476 miles on 14 gallons of gas. Write an equation relating the distance d to the number of gallons g. How many
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What is the product of (1.9*10^-3)(2*10^4)
RoseWind [281]

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to solve use the distributive property and multiply

Step-by-step explanation:

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3 years ago
Read 2 more answers
A standard deck of cards has 52 cards, 4 of each type (Ace, King, Queen, Jack, 10,...,2). From a well-shuffled deck, you are dea
Wewaii [24]

Answer:

a)%85,5

b)%92,2

Step-by-step explanation:

a) To determine the probability of getting a hand with at least one face, we need to calculate the probability of the hand without any face firstly.

(36/52)*(35/51)*(34/50)*(33/49)*(32/48)=0,145

Then, we need to deduct this value from the probability 1

1-0,145=0,855

The probability of the hand with at least one face is %85,5.

b)To determine the probability of a hand with at least one ace and face we will track the same road again.

(32/52)*(31/51)*(30/50)*(29/49)*(28/48)=0,0775

Then, we need to deduct this value from the probability 1

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3 0
3 years ago
A jar of peanut butter contains 454 g with a standard deviation of 10.2 g. Find the probability that a jar contains more than 46
Fofino [41]

Answer:

The probability that a jar contains more than 466 g is 0.119.

Step-by-step explanation:

We are given that a jar of peanut butter contains a mean of 454 g with a standard deviation of 10.2 g.

Let X = <u><em>Amount of peanut butter in a jar</em></u>

The z-score probability distribution for the normal distribution is given by;

                                Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 454 g

           \sigma = standard deviation = 10.2 g

So, X ~ Normal(\mu=454 , \sigma^{2} = 10.2^{2})

Now, the probability that a jar contains more than 466 g is given by = P(X > 466 g)

            P(X > 466 g) = P( \frac{X-\mu}{\sigma} > \frac{466-454}{10.2} ) = P(Z > 1.18) = 1 - P(Z \leq 1.18)

                                                                  = 1 - 0.881 = <u>0.119</u>

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

4 0
3 years ago
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