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Vsevolod [243]
3 years ago
7

1. The area of a square with side length x, where the side length is decreased by 3, the area is

Mathematics
1 answer:
Murljashka [212]3 years ago
6 0

Answer:

2x^2-12x+22

Step-by-step explanation:

Let's follow what the problem asks us:

  • "The area of a square with side length x"

this is the formula for area: area=side*side=side^2

since the side length is x, the initial area is: x^2

  • Now, "where the side length is decreased by 3":

The side is now (x-3), thus the area is: (x-3)^2=x^2-6x+9

  • "the area is multiplied by 2"

we had the area x^2-6x+9, when we multiply by 2:

(2)(x^2-6x+9)=2x^2-12x+18

  • And finally " then 4 square units are added to the area.​"

this is: 2x^2-12x+18 + 4=2x^2-12x+22

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