Question

1. The area of a square with side length x, where the side length is decreased by 3, the area is

Answer 1

Answer:

$2x^2-12x+22$

Step-by-step explanation:

Let's follow what the problem asks us:

• "The area of a square with side length x"

this is the formula for area: $area=side*side=side^2$

since the side length is x, the initial area is: $x^2$

• Now, "where the side length is decreased by 3":

The side is now $(x-3)$, thus the area is: $(x-3)^2=x^2-6x+9$

• "the area is multiplied by 2"

we had the area $x^2-6x+9$, when we multiply by 2:

$(2)(x^2-6x+9)=2x^2-12x+18$

• And finally " then 4 square units are added to the area.​"

this is: $2x^2-12x+18 + 4=2x^2-12x+22$