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3 years ago

If f(x)=x^2, find f(-3)

Mathematics

2 answers:

patriot [66]3 years ago

7 0

Answer: f(-3) = 9

Step-by-step explanation:

Plug in -3 for x

f(-3) = (-3)^2

Square -3

(-3)^2 = 9

Andreyy893 years ago

4 0

Answer:

f(-3)=9

Step-by-step explanation:

f(x)= $x^{2}$

To find f(-3) replace x in the function by -3

Therefore:

f(−3)=(−3)^2

=−1^2 × 3^2 =1 × 9 = 9

HOPE THIS HELPS

HAVE A GOOD DAY:)

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What is the factorization of 729^15+1000?

igomit [66]

Answer:

The factorization of $729x^{15} +1000$ is $(9x^{5} +10)(81x^{10} -90x^{5} +100)$

Step-by-step explanation:

This is a case of factorization by sum and difference of cubes, this type of factorization applies only in binomials of the form $(a^{3} +b^{3} )$ or $(a^{3} -b^{3})$ . It is easy to recognize because the coefficients of the terms are perfect cube numbers (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).

Let's solve the factorization of $729x^{15} +1000$ by using the sum and difference of cubes factorization.

1.) We calculate the cubic root of each term in the equation $729x^{15} +1000$ , and the exponent of the letter x is divided by 3.

$\sqrt[3]{729x^{15}} =9x^{5}$

$1000=10^{3}$ then $\sqrt[3]{10^{3}} =10$

So, we got that

$729x^{15} +1000=(9x^{5})^{3} + (10)^{3}$ which has the form of $(a^{3} +b^{3} )$ which means is a sum of cubes.

Sum of cubes

$(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})$

with $a= 9x^{5}$ y $b=10$

2.) Solving the sum of cubes.

$(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )$

$(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)$

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Secants P N and L N intersect at point N outside of the circle. Secant P N intersects the circle at point Q and secant L N inter

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Answer:

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In the diagram, the length of the external portion of the secant segment PN is X

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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