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2 years ago

Log 64 = x. Find X ⁴

Mathematics

2 answers:

ozzi2 years ago

6 0

Answer:

Step-by-step explanation:

Rewrite the logarithmic notation to index notation.

4^x=64

Change 64 to index notation

ie 64 = 4^3

Since the base is the same(4) cancel them out

You remain with x = 3

katrin [286]2 years ago

5 0

I think you it already Bc the other person put it

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ki77a [65]

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Step-by-step explanation:

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3 years ago

The selling price for a classic speedboat is $10,000, which is $2000 less than two times its original price. What was the origin

Luda [366]

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3 years ago

A rectangular poster is 5 dm long and 3 dm wide. Sara wants to paint the whole poster. Find the area of the poster in square cm.

Zina [86]

Answer:

$\boxed{1500cm^{2} }$

Step-by-step explanation:

Area = Length × Width

→ Identify the length and width

Length = 5 and Width = 3

→ Substitute in the values

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2 years ago

A group of students are planning a mural at a wall the rectangular wall has dimensions of (6x+7) by (8x+5) and they are planning

zvonat [6]

Answer: $46x^2+73x+15$

Step-by-step explanation:

The area of a rectangle can be calculated with the formula:

$A=lw$

l: the length of the rectangle.

w: the width of the rectangle.

The area of the remaning wall after the mural has been painted, will be the difference of the area of the wall and the area of the mural.

Knowing that the dimensions of the wall are $(6x+7)$ by $(8x+5)$ , its area is:

$A_w=(6x+7)(8x+5)\\\\A_w=48x^2+30x+56x+35\\\\A_w=48x^2+86x+35$

As they are planning that the dimensions of the mural be $(x+4)$ by $(2x+5)$ , its area is:

$A_m=(x+4)(2x+5)\\\\A_m=2x^2+5x+8x+20\\\\A_m=2x^2+13x+20$

Then the area of the remaining wall after the mural has been painted is:

$A_{(remaining)}=A_w-A_m\\\\A_{(remaining)}=48x^2+86x+35-(2x^2+13x+20)\\\\A_{(remaining)}=48x^2+86x+35-2x^2-13x-20\\\\A_{(remaining)}=46x^2+73x+15$

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3 years ago

What is the prime factorization of 50? 2 x 5 2 x 25 2 x 5 x 5 2 x 2 x 5

NeX [460]

Answer:

i think it is 2×5×5

hope it helps

7 0

2 years ago