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3 years ago

WHat is the length of AC

Mathematics

2 answers:

sashaice [31]3 years ago

8 0

Answer:

1.5*4 = 6

Step-by-step explanation:

Since side length "IH" dilated to "BA" by the scale factor of 4, the same patter would be followed to dilate "HJ" to "AC", so you have to multiply side length 1.5 (HJ) by the scale factor of 4 to get "AC".

Hope this helped, good luck!

Juli2301 [7.4K]3 years ago

7 0

Answer:

multiply 7.5 by 4

Step-by-step explanation:

múltiply 7.5 by 4

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3 years ago

Evaluate without using a calculator (x2y-3)0+x1/3-(4x)1/2 when x = 64 and y = 27. Show work.

aleksley [76]

Given:

The expression is:

$(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}$

To find:

The value of the given expression when $x=64$ and $y=27$ .

Solution:

We have,

$(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}$

Putting $x=64$ and $y=27$ , we get

$=((64)^2(27)-3)^0+(64)^{\frac{1}{3}}-(4(64))^{\frac{1}{2}}$

It can be written as

$=((64)^2(27)-3)^0+(4^3)^{\frac{1}{3}}-(4)^{\frac{1}{2}}(64)^{\frac{1}{2}}$

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$=5-16$

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Therefore, the value of the given expression $-11$ when $x=64$ and $y=27$ .

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