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Mariana [72]
3 years ago
7

Ive never seen a question like this tbh

Mathematics
2 answers:
Vikki [24]3 years ago
6 0
The formula A=1/2bh is used to find the area of a triangle. You can find from the diagram that the base of this triangle is 9cm, and the height is 4cm. Plug those numbers into the area of a triangle formula.

A=1/2(9)(4)

Multiply to get 18 square cm, which is choice D.
bulgar [2K]3 years ago
4 0
Easiest question I have ever seen! :)
We know the formula of the area of a triangle
  =\frac{1}{2}×base×height
 The height given is 4 cm (we should take the perpendicular height)
  And the base length is 8 cm
Simply, we just substitute the given numbers
  =\frac{1}{2}×8×4
  =18 cm²
The answer is D: 18 square m
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What is the product in simplest form.
Alex787 [66]

Answer:

a)

-  \frac{9}{22}

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3 years ago
Give 5 Examples of Linear Equation in Two Variables​
jeka94
Dang bro I got no clue
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3 years ago
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What is the value of 10×+z=150<br>​
JulijaS [17]

Answer:

<h2><u><em>15</em></u></h2>

Step-by-step explanation:

what is the value of 10×+z=150

10× (+z) = 150

10 × z = 150

z = 150 : 10

z = 15

-----------------------

check

10 × 15 = 150

the answer is good

8 0
3 years ago
Read 2 more answers
Fine the value of the x in the triangle shown below.
Sever21 [200]

Answer:

x=28

Step-by-step explanation:

The interior angles of a triangle must add to 180 degrees

Therefore,

79+73+x=180

Combine like terms by adding 79 and 73

152+x=180

To solve for x, get x by itself. Since 152 is being added to x, subtract 152 from both sides. This will cancel the 152, and leave x by itself.

152-152+x=180-152

x=28

So, x is equal to 28 degrees

8 0
4 years ago
Read 2 more answers
A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey
Lubov Fominskaja [6]

Answer:

Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779

And the deviation would be:

Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54

Step-by-step explanation:

For this case we have the following distribution given:

X        0         1       2       3       4         5        6

P(X)  0.3   0.25   0.2   0.12   0.07   0.04   0.02

For this case we need to find first the expected value given by:

E(X) = \sum_{i=1}^n X_i P(X_I)

And replacing we got:

E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61

Now we can find the second moment given by:

E(X^2) =\sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97

And the variance would be given by:

Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779

And the deviation would be:

Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54

 

8 0
4 years ago
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