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Scorpion4ik [409]
4 years ago
12

Adjust to scientific notation: 80.1*10^-3

Mathematics
2 answers:
jekas [21]4 years ago
7 0
80.1*10^-3

Divide both sides by 10

8.01*10^-2

And that’s the answer.
galben [10]4 years ago
6 0
The answer is 1/10 come again
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Please help i need it !!!
Sedbober [7]

Answer:

x=7

Step-by-step explanation:

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3 years ago
What happens to the value of the expression 3 y over <br> 2 y as y increases
vladimir1956 [14]
It starts becoming bigger :)
8 0
4 years ago
How do I solve for this
Anon25 [30]

Answer: for 90 degrees it will be 1

for 180 degrees it will be \sqrt{2}/2

Step-by-step explanation:

7 0
3 years ago
In Exercise sketch the graph of the function.<br> f(x) = ex + 3
Tju [1.3M]

Answer:

f(x) = e^x + 3

Step-by-step explanation:

We are given the following function in the question:

f(x) = e^x + 3

We have to graph this function.

Properties of given function are:

  • e is a constant and have a value of e = 2.718281828....
  • The function does not pass through origin
  • At x = 0, f(x) = 4
  • The domain for the given function is all real numbers.
  • The range of the given function is (3, \infty)

The attached image shows the graph for given function.

5 0
3 years ago
A person traveling from Seattle to Sydney has three airlines to choose from. 40% of travelers choose airline A, and this airline
dalvyx [7]

Answer:

46.67% probability that they flew with airline B.

Step-by-step explanation:

We have these following probabilities:

A 40% probability that a traveler chooses airline A.

A 35% probability that a traveled chooses airline B.

A 25% probability that a traveler chooses airline C.

If a passenger chooses airline A, a 10% probability that he arrives late.

If a passenger chooses airline B, a 15% probability that he arrives late.

If a passenger chooses airline C, a 8% probability that he arrives late.

If a randomly selected traveler is on a flight from Seattle which arrives late to Sydney, what is the probability that they flew with airline B?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So

What is the probability that the traveler flew with airline B, given that he was late?

P(B) is the probability that he flew with airline B.

So P(B) = 0.35

P(A/B) is the probability of being late when traveling with airline B. So P(A/B) = 0.15.

P(A) is the probability of being late. This is the sum of 10% of 40%(airline A), 15% of 35%(airline B) and 8% of 25%(airline C).

So

P(A) = 0.1*0.4 + 0.15*0.35 + 0.08*0.25 = 0.1125

Probability

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.35*0.15}{0.1125} = 0.4667

46.67% probability that they flew with airline B.

5 0
3 years ago
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