1. Definition of bisector
2. ASA congruence theorem or ASA Postulate
A = a^2.....where " a " is the length of one side
A = 79
79 = a^2...take sqrt of both sides, eliminating the ^2
sqrt 79 = a
8.89 = a
so the length of one side is approximately 8.89 ft <==
A) area of square = base*height/////Triangle= 0.5*base*height
=(a^1/3*b^3/4)*(a^2/3*b^1/2)+(1/2*a^1/3*b^3/4*a^2/3*b^1/4)
=(a^1*b^5/4)+(1/2*a^1*b^1)
=(a*b^5/4)+(1/2*a*b)
B) a^2+b^2=c^2 (pythagorean theorem)
((27^2/3)*(16^1/4))^2 + (27^1/3)*(16^3/4)
(9*2=(18^2))=324 + (3*8= 24^2)= 576
324+576= 900
(900)^1/2= 30
hypotenuse= 30
C)( a^2/3*b^1/2)= 36*2(two sides)= 72
(a^1/3b^3/4)=24
(a^2/3*b^1/4)= 18
72+24+18+30(hypotenuse)= 144=perimeter
Answer:
C
Step-by-step explanation:
after 0, there are 3 lines on the graph, if you count by 1 to 3 on it, it is on 1/3 of it. Hope that this helps you and have a great day :)
