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3 years ago

X^2-18x+67=0 Solve the quadratic equation by completing the square.

Mathematics

1 answer:

Assoli18 [71]3 years ago

5 0

Answer:

x = 9 ± √14

Step-by-step explanation:

x² − 18x + 67 = 0

Move the constant to the other side:

x² − 18x = -67

Take half of -18, square it, and add to both sides.

(-18/2)² = (-9)² = 81

x² − 18x + 81 = -67 + 81

x² − 18x + 81 = 14

Factor the perfect square:

(x − 9)² = 14

Solve for x:

x − 9 = ±√14

x = 9 ± √14

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Another way to find out which value would be a solution to u/7 - 1 = 7 is to solve for u.

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The only solution to this equation is when u = 56.

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3 years ago

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Dmitrij [34]

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if x =4 and y =-3

F = $\frac{ x^{2}-4y }{2} = \frac{ (4)^{2}-4(-3) }{2} = \frac{ 16+12 }{2} = 14$

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