#1- Jennifer made a box plot to summarize this data. 124, 118, 129, 139, 133, 129, 142, 135, 122, 137. What is the median, the l
svp [43]
Answer:
B or
Lower quartile: 124
Median: 131
Upper quartile: 137
Step-by-step explanation:
To find the median first make the data in order from greatest to least:
118,122,124,129,129,133,135,137,139,142
Then find the middle 2 numbers which are 129 and 133
129+133=262 (divide by 2 to find average) so
median= 262/2=131
To find the Lower quartile find the number in the middle of the first 5 numbers which is 124
To find the Upper quartile find the number in the middle of the second 5 numbers which is 137 so
B or
Lower quartile: 124
Median: 131
Upper quartile: 137
The answer is J, t = 1/9u
An=A1 r ^(n-1)
192= 3 r ^(4-1)
192 = 3 r^3
64 = r^3
r = 4
equation:
An=3 (4)^(n-1)
6th term:
An= 3 (4)^(6-1)
An= 3072
I think this is right :)
Answer:
-5 ≤ n ≤ 3
Step-by-step explanation:
Firstly we solve the equation two at a time;
5n + 17 ≥ n - 3
5n - n ≥ -3 - 17
4n ≥ -20
n ≥ -5
-5 ≤ n
n - 3 ≥ -15 + 5n
n - 5n ≥ -15 + 3
-4n ≥ -12
-n ≥ -3
n ≤ 3
Therefore,
5n+17 ≥ n–3 ≥ –15+5n, becomes
-5 ≤ n ≤ 3
3 ways (uncertain)
1 red or blue or green + 3 other colours
