Answer:
3.38/6.21=54.428% (0.54428)
Step-by-step explanation:
biocapacity of grazing land of 0.85 ha/person+biocapacity of forest land of 2.53 ha/person
2.53+0.85=3.38
the percentage of biocapacity from grazing and forest land
3.38/6.21=54.428% (0.54428)
Answer:
Standard error = 0.070
Step-by-step explanation:
Formula for the standard error of the distribution of differences in sample proportions is;
σ_(A - B) = √((p_a^(1 - p_a^)/n_a) + (p_b^(1 - p_b^)/n_b))
We are given;
p_a^ = 0.48
n_a = 80
p_b^ = 0.13
n_b = 66
Thus;
σ_(A - B) = √((0.48(1 - 0.48)/80) + (0.14(1 - 0.13)/66))
σ_(A - B) = √0.00496545455
σ_(A - B) = 0.070
Lets get all the information we need first.
A week has 7 days, you practice 30 min each day, so in a week you will practice a total time t of 30 min for 7 times, that is:
t = 7day(30 min/day)
t = 210 min
So in a week you will practice a total of 210 minutes.
Answer:
4/75
Step-by-step explanation:
Answer:
(y - 1)(5y - 2)
Solution:
Factor:
2 - y(7 - 5y)
Apply the Distributive Property:
2 - 7y + 5y²
Reorder the expression:
5y² - 7y + 2
Rewrite the term:
5y² - 5y - 2y + 2
Regroup terms into two proportional parts:
(5y² - 5y) + ( -2y + 2)
Factor Greatest Common Factors out:
5y(y - 1) - 2(y - 1)
(y - 1)(5y - 2)
