The method of changing a degree to a radian is to multiply with 1/180
Answer:
X is 50
Step-by-step explanation:
Answer:
Question 1 (1 point)
1. An object has a mass of 25g and a volume of 5ml
a
10
b
8
c
5
d
7
Question 2 (1 point)
2. An object has a mass of 30g and a volume of15ml. What is the density?
a
10
b
2
c
3
d
5
Question 3 (1 point)
3. An object has a mass of 200g and a volume of 100ml. What is the density?
a
2
b
4
c
6
d
8
Question 4 (1 point)
4. An object has a mass of 17g and a volume of 2ml. What is the density?
a
2.4
b
2
c
8
d
8.5
Question 5 (1 point)
5. An object has a mass of 20g and a volume of 5ml. What is the density?
a
2
b
4
c
10
d
2.5
Question 6 (1 point)
6. An object has a mass of 75g and a volume of 75ml. What is the density?
a
6
b
1
c
7
d
8
Question 7 (1 point)
7. An object has a volume of 100ml and a mass of 2oo ml. What is the density?
a
0.5
b
1
c
4
d
2.5
Question 8 (1 point)
8. An object has a volume of 5ml and a mass of 650 g. What is the density?
a
110
b
120
c
130
d
200
Question 9 (1 point)
9. An object has a mass of 15g and a volume of 5ml. What is the density?
a
2.5
b
7
c
3
d
2.56
Question 10 (1 point)
10. An object has a mass of 13g and a volume of 2ml. What is the density?
a
6.5
b
3.7
c
4
d
Step-by-step explanation:
Using the normal distribution, it is found that 0.0329 = 3.29% of the population are considered to be potential leaders.
In a <em>normal distribution</em> with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of 550, hence
.
- The standard deviation is of 125, hence
.
The proportion of the population considered to be potential leaders is <u>1 subtracted by the p-value of Z when X = 780</u>, hence:



has a p-value of 0.9671.
1 - 0.9671 = 0.0329
0.0329 = 3.29% of the population are considered to be potential leaders.
To learn more about the normal distribution, you can take a look at brainly.com/question/24663213