Answer:
55.32% probability that a late package was delivered by express delivery service 2
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Late delivery.
Event B: Service 2 was used.
A certain company sends 35% of its overnight mail parcels via express delivery service 1 and the rest by express delivery service 2.
100 - 35 = 65%.
So 
Service 2 has a record of 2.0% of packages being delivered late.
This means that 
Probability of a late delivery.
35% from service 1. Of those, 3% are late.
65% from service 2. Of those, 2% are late.
So
What is the probability that a late package was delivered by express delivery service 2
55.32% probability that a late package was delivered by express delivery service 2
Answer:
<u>The width of the neighborhood block is 0.05 or 1/20 miles</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
Number of times Bijan run around the neighborhood block = 20
Total distance Bijan run = 8 miles
Length of the block = 3/20 = 0.15 miles
2. Use the formula for the perimeter of the neighborhood block and the reciprocal to find the width w of the city block.
Let's find the perimeter of the neighborhood block and the width, this way:
A. Rule of Three Direct for find the perimeter:
Laps Distance
20 8 miles
1 x miles
x * 20 = 8
20x = 8
x = 8/20
x = 2/5 or 0.4 miles
B. Formula of the perimeter to find the width
Perimeter = 2 Length + 2 Width
Replacing with the real values we know:
0.4 = 2 * 0.15 + 2w
0.4 = 0.3 + 2w
0.4 - 0.3 = 2w
0.1 = 2w
w = 0.1/2
w = 0.05 miles
<u>The width of the neighborhood block is 0.05 or 1/20 miles</u>
Answer:
A.
Step-by-step explanation:
So you would have f(3) = 3 + 
f(3) = 3 + 1
f(3) = 4
