The number of days when the season pass would be less expensive than the daily pass is 5 days.
<h3>How many days would the season pass be less expensive?</h3>
The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)
$70d + $20d = $90d
The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)
$300 + $20d
When the season pass becomes less expensive, the inequality equation is:
Daily pass > season pass
$90d > $300 + $20d
In order to determine the value of d, take the following steps:
Combine and add similar terms: $90d - $20d > $300
70d > $300
Divide both sides by 70 d > $300 / 70
d > 4.3 days
Approximately 5 days.
To learn more about how to calculate inequality, please check: brainly.com/question/13306871
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Since this is a problem in exponential growth/decay, y = ab^x is the formula that will be used to solve this problem.
The initial value, "a", is the value you start out with and in this case, it is $2000.
The growth/decay factor is what "b" represents, and it is 4%. We need to change the percentage into a decimal, so we will take the percent symbol, change it into a decimal, and move it two places to the left. This is make it 0.04. The problem also mentions interest, implying an exponential growth. Therefore, you will add 0.04 by 1: 1+0.04 = 1.04.
The "x" represents an amount of time. It is 5 years. The equation should be written like this:
y = 2000(1.04)^5
y = 2433.30. When rounded to the nearest dollar, it is $2433.
I plugged it in to a truncated square pyramid calculator and got v=76
the formula for this shape is V=1/3(A squared+AB+B squared)H.
If what ? What is the If part, so I can help answer your question.
