Just this question I've tried but don't understand it

Define z_alpha to be a z-score with an area of alpha to the right. For Example: z_0.10 means P(Z > z_0.10) = 0.10. We would a

Reptile [31]

Answer:

a) P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

And for this case the two values are : $z_{crit}= \pm 1.96$

b) P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates $\alpha/2$ of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

c) For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got $z_{\alpha/2}=1.64$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Part a

P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

And for this case the two values are : $z_{crit}= \pm 1.96$

Part b

P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates $\alpha/2$ of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

Part c

For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got $z_{\alpha/2}=1.64$

6 0

3 years ago

Solve the following equation algebraically: x^2=20

Zielflug [23.3K]

Answer:

x = ± 2 $\sqrt{5}$

Step-by-step explanation:

Given

x² = 20 ( take the square root of both sides )

x = ± $\sqrt{20}$ = ± $\sqrt{4(5)}$ = ± 2 $\sqrt{5}$

6 0

3 years ago

Read 2 more answers

Type an integer or decimal 0.16(y-5)+0.12y=0.20y-0.9

Over [174]

Answer:

16y

Step-by-step explanation:

4 0

3 years ago

Camille is working in craft class to create new pillows for her room. Each pillow will be made from exactly 36 in2 of material.

Ann [662]

The best design for Camille is the one in which the area matches the total of material she wants to use for each pillow.

<h3>What should Camille consider for her design?</h3>

Camille's main restriction is the material per pillow since she needs every pillow to use only 36 inches of material. Due to this, she needs to make sure the design meets this requirement.

<h3>How to determine how much material each design requires?</h3>

The best method for this is to calculate the area of the design by using the sides. Here are the most common formulas:

Triangular design: Base x height/ 2
Squared or rectangular design: side x side
Circular design: A = π r²

Based on this, the best design is the one that adjusts to the material available.

Note: This question is incomplete because there is no information about the designs; due to this, I answered it based on general knowledge.

Learn more about area in: brainly.com/question/16151549

4 0

2 years ago

964 two correct wrong place

Anvisha [2.4K]

Answer:

679

Step-by-step explanation:

The goal of this exercise is to find a three digit number given five statements.

1 - We can conclude that two digits out of 964 are correct but in the wrong place.

2 - One digit out of 147 is correct, but in the wrong place

3 - One digit out of 189 is correct and in the right place. Since 1 is on the same place in 147 and 189, 1 is not the correct digit. The correct digit is either 8 or 9.

4 - One digit out of 286 is correct, but in the wrong place. Since 8 is on the same place in 189 and 286, 8 is not the correct digit. We can then conclude that 9 is correct (statement 3) and in the right place (third) and that either 2 or 6 are correct but in the wrong place.

5 - 523 are all wrong. We can then conclude that 6 is correct and that is not in the third or second place, which leaves it in the first place.

If 1 and 4 are incorrect, from the second statement, we infer that 7 is the remaining correct digit at the second place.

Therefore the number is 679

7 0

3 years ago