Let
x = number of rs 50
y = number of rs 20
z = number of rs 10
Because there are 25 total notes,
x + y + z = 25 (1)
The ratio of rs 50 to rs 20 is 3:5, therefore
x = 0.6y (2)
The total amount is rs 590, therefore
50x + 20y + 10z = 590
or
5x + 2y + z = 59 (3)
Subtract (1) from (3).
4x + y = 34 (4)
Substitute (2) into (4).
4*(0.6y) + y = 34
3.4y = 34
y = 10
From (2), obtain
x = 6
From (1), obtain
z = 25 - 6 - 10 = 9
Answer:
Kaveri has
6 rs 50 notes,
10 rs 20 notes,
9 rs 10 notes.
Three hundred twenty-five thousand, eight hundred nine
The Answer is b The numerical values of the circumference and area are equal.
Your answer is C hope this helps
Answer:
2m^2 + 21m + 147 + 1023/(m - 7)
Step-by-step explanation:
m - 7 ) 2m^3 + 7m^2 + 0m - 6 ( 2m^2 + 21m + 147 <--- Quotient
2m^3 - 14m^2
21m^2 + 0m
21m^2 - 147m
+ 147m - 6
+ 147m - 1029
1023 <--- remainder.