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3 years ago

3 pounds of bananas cost $7. At this rate, how much does 1 pound of bananas cost?

Mathematics

1 answer:

Furkat [3]3 years ago

7 0

Answer:

Step-by-step explanation:

To find the cost of 1 pound of bananas we use ratio and proportion

From the question

3 pounds of bananas costs $7

Then 1 pound will cost

$\frac{7 \times 1}{3} = \frac{7}{3 } \\ = 2.33333...$

We have the final answer as

Hope this helps you

You might be interested in

The distribution of passenger vehicle speeds traveling on a certain freeway in California is nearly normal with a mean of 71.5 m

Zinaida [17]

Answer:

$G = 0.007523$

The number of cars the highway patrol officer would watch before a car that is seen is $E(X) = 1.6027$

The standard deviation is $s = 0.9829$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 71.5 \ miles/hour$

The standard deviation is $\sigma = 4.75 \ miles/hour$

The speed limit is $x = 70 \ miles /hour$

Generally the probability of getting a car that is moving with speed greater than the speed limit is mathematically represented as

$p =P(X > x ) = P(X > 70) = P(\frac{X - \mu }{\sigma } > \frac{70 - 71.5 }{4.75})$

=> $p= P(X > 70) = P(\frac{X - \mu }{\sigma } > \frac{70 - 71.5 }{4.75})$

=> $p= P(X > 70) = P(\frac{X - \mu }{\sigma } > -0.31579 )$

Here

$\frac{X - \mu }{\sigma } = Z(The \ standardized \ value \ of X )$

=> $p= P(X > 70) = P(Z > -0.31579 )$

From the z-table

$p = P(Z > -0.31579 ) = 0.62392$

$p = P(X > 70) = 0.62392$

Generally the probability of getting a car that is not moving with speed greater than the speed limit is mathematically represented as

$q = 1 - p$

=> $q = 1 - 0.62392$

=> $q = 0.37608$

Generally the probability of getting 5 cars that are not speeding is mathematically represented as

$G = q^5$

=> $G = (0.37608)^5$

=> $G = 0.007523$

Generally the number of cars that the highway patrol officer is expected to watch until the first car that is speeding is gotten is mathematically represented as

$E(X) = \frac{1}{p}$

=> $E(X) = \frac{1}{0.62392}$

=> $E(X) = 1.6027$

Generally the standard deviation is mathematically represented as

$s = \sqrt{\frac{1 - p }{ p^2} }$

=> $s = \sqrt{\frac{1 -0.62392 }{ (0.62392)^2} }$

=> $s = 0.9829$

8 0

3 years ago

Which is correct?

Alja [10]

Below is the conversion table for letter A to D:
1 deciliter = 0.001 hectoliters
1 liter = 100 centiliters
1 kilolieter = 10 hectoliter
1 liter = 10 deciliter

The correct one would be letter C - There are 6.8 kiloliters in 68 hectoliters. Since 1 kiloliters (kl) is equal to 10 hectoliters (hl), 6.8 kl times 10 is equal to 68 hl.

7 0

4 years ago

Answer number 1 please.

Minchanka [31]

$\sf {a}^{2} = {13}^{2} - {5}^{2}$