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3 years ago

Whats the answer???

Mathematics

2 answers:

Ray Of Light [21]3 years ago

8 0

Answer:

Divide the figure into 5 squares.

then find the area 1 square and multiply with 5.

Area of square=s*s

=4 cm²

Then 5*4=20 cm²

<u>so c is the correct option.</u>

<u><em>HOPE IT HELPS!</em></u>

ira [324]3 years ago

7 0

Answer:The answer is C 20 cm^3

Step-by-step explanation:

You just multiply 2 by 2 and get 4 and you have 5 squares and you get 4 times 5 which is 20 cm^3

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Can you help please?<br><br>

Vilka [71]

In 2 hours,hope this helps :)

7 0

3 years ago

PLEASE HELP LOOK AT PICTURE YOU ANSWER I GIVE BRAINLIEST

Norma-Jean [14]

Answer:

Your answer would be 26.64cm.

A step-by-step explanation for you, peabrain:

For all four sides:

1.8cm x 2.7cm = 4.86cm

4.8cm x 4 sides = 19.44cm

For the top and bottom:

1.8cm x 1.8cm = 3.6

3.6cm x 2 sides = 7.2cm

For the complete LSA (lateral surface area):

19.44 + 7.2cm = 26.64cm

Do not forget to round, if that is in your homework instructions :-)!

4 0

3 years ago

Read 2 more answers

The coordinates G(7,3), H(9, 0), (5, -1) form what type of polygon?

Marrrta [24]

Answer:

Is an acute triangle

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

G(7,3), H(9, 0), I(5, -1)

step 1

Find the distance GH

substitute in the formula

$d=\sqrt{(0-3)^{2}+(9-7)^{2}}$

$d=\sqrt{(-3)^{2}+(2)^{2}}$

$GH=\sqrt{13}\ units$

step 2

Find the distance IH

substitute in the formula

$d=\sqrt{(0+1)^{2}+(9-5)^{2}}$

$d=\sqrt{(1)^{2}+(4)^{2}}$

$IH=\sqrt{17}\ units$

step 3

Find the distance GI

substitute in the formula

$d=\sqrt{(-1-3)^{2}+(5-7)^{2}}$

$d=\sqrt{(-4)^{2}+(-2)^{2}}$

$GI=\sqrt{20}\ units$

step 4

Verify what type of triangle is the polygon

we know that

If applying the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$ ----> is a right triangle

$c^{2}> a^{2}+b^{2}$ ----> is an obtuse triangle

$c^{2}< a^{2}+b^{2}$ ----> is an acute triangle

where

c is the greater side

we have

$c=\sqrt{20}\ units$

$a=\sqrt{17}\ units$

$b=\sqrt{13}\ units$

substitute

$c^{2}= (\sqrt{20})^{2}=20$

$a^{2}+b^{2}=(\sqrt{17})^{2}+(\sqrt{13})^{2}=30$

therefore

$c^{2}< a^{2}+b^{2}$

Is an acute triangle

6 0

3 years ago

Read 2 more answers

I need help with my math I'm doing solving equations using addition and subtraction

Flura [38]

N+3=7. To find n, you need to have it by itself, so you can do that by subtracting 3 on both sides, so it would look like: n+3-3=7-3. Then you have n=4.

3 0

3 years ago

Read 2 more answers

Really need help in these two questions!!!! Thank you math experts!!!!

const2013 [10]

<h3><u>Answers</u><u>:</u></h3>

1. $b = 7$ ,

$a = 12$

$b = - 1$ ,

$a = - 4$

2. $= 10$

See attached images for explanation.

3 0

2 years ago

Whats the answer???​

Whats the answer???