The rate at which the ice changes is -3/8 lb per hr
<h3>What is the rate the ice changes?</h3>
The given parameters are:
Changes =1 3/4 lb to 1/4 lb
Time = 1/4 hr.
The rate the ice changes is calculated as:
Rate = Change/Time
So, we have
Rate = (1/4 lb - 1 3/4 lb)/(1/4 hr)
Evaluate the difference
Rate = (-1 1/2 lb)/(1/4 hr)
Evaluate the quotient
Rate = -3/8 lb per hr
Hence, the rate at which the ice changes is -3/8 lb per hr
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Answer:
58.6
Step-by-step explanation:
Use the formula 
solving for x (b)
= 
≈58.58327
and 58.58327 rounds to 58.6
Answer:
1/4 hopefully this helps you with work
Answer:
He squared the numbers inside without following the appropriate rule
Step-by-step explanation:
<u>what he should have done </u>
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Yes, 8 is a solution to the equation
