Answer:
Step-by-step explanation:
Let the first integer be x, then the next is x+1.
x(x + 1) = 3(x + 1) + 4
x^2 + x = 3x+ 3 + 4
x^2 + x - 3x - 7 = 0
x^2 - 2x - 7 = 0
Solving this does not give an integer so maybe there's something wrong with the question??
Answer:
It has no solution
Step-by-step explanation:
Here we have to draw the graph of y = 0.5x^2 + 3 and y = -4x^2 + 24x - 35.
I have attached the graph of these two functions.
Since the graphs of the functions didn't cut each other.
Therefore, answer is "it has no solution."
Hope this will helpful.
Thank you.
The Pythagorean Theorem states that a^2+b^2=c^2
We already have:
A^2+6^2=117
All we need to do is find the missing A by subtract b from c.
117-36=81
Now the square root of 81, 9.
So, x is 9 cm.
Answer:
So starting off with 1a f(4)
We simply substitute x with 4 for the function
f(4)=2(4)-5
f(4)=8-5
f(4)=3
Next 1b, here it's a little different since you have to multiply the functions I think ( please correct me if I'm wrong).
gf(4), basically means functions g and f are being multiplied and their variables are being substituted with 4.
g(4)=4^2+3
g(4)=16+3
g(4)=19
and we also know from before that f(4)=3, so we'll do 19 times 3 which is 57
For the next two, I may be wrong, but I'm still going to try:
anything to the power of a negative is a fraction so for f^-1(x)=2x-5 we'll have 1/f(x)=x/2+5/2
And then for g^-1, we'll have 1/g(x)=
Hope I helped :)