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3 years ago

What expression represents the product of 3 less than twice x and 2 more than the quantity 3 times x?

1 answer:

8 0

"3 less than twice 'x' " . . . . that's (2x - 3)

" 2 more than the quantity (3 x) " . . . . . that's (3x + 2)

Their product is
(2x - 3) (3x + 2) .

If you want to expand it to a single expression, perform the multiplication,
and you have
6x² - 5x - 6 .

You might be interested in

The product of two rational numbers is 34.77. If one of the numbers is 6.1, what is the other number?

erik [133]

Answer:

5.7

Step-by-step explanation:

6 0

3 years ago

Seven less than the product of a number n and 1/6 is no more than 94

antiseptic1488 [7]

Answer:

n ≤ 606

Step-by-step explanation:

Seven less than the product of a number n and 1/6 is no more than 94, translating:

n*1/6 - 7 ≤ 94

Solving for n:

n/6 ≤ 94 + 7
n/6 ≤ 101
n ≤ 101*6
n ≤ 606

4 0

2 years ago

Please help me!!!!! i need full answer.

salantis [7]

Answer:

see explanation

Step-by-step explanation:

Using the sum/ difference → product formula

cos x - cos y = - 2sin( $\frac{x+y}{2}$ )sin ( $\frac{x-y}{2}$ )

sin x - sin y = 2cos ( $\frac{x+y}{2}$ )sin ( $\frac{x-y}{2}$ )

Given

(cosA - cosB)² + (sinA - sinB )²

= [ - 2sin( $\frac{A+B}{2}$ )sin( $\frac{A-B}{2}$ ) ]² + [ 2cos( $\frac{A+B}{2}$ )sin( $\frac{A-B}{2}$ ) ]²

= 4sin² ( $\frac{A+B}{2}$ )sin² ( $\frac{A-B}{2}$ ) + 4cos² ( $\frac{A+B}{2}$ )sin² ( $\frac{A-B}{2}$ )

= 4sin² ( $\frac{A-B}{2}$ )[ sin² ( $\frac{A+B}{2}$ ) + cos² ( $\frac{A+B}{2}$ ) ← sin²x + cos²x = 1

= 4sin² ( $\frac{A-B}{2}$ ) × 1

= 4sin² ( $\frac{A-B}{2}$ ) = right side ⇒ proven

4 0

3 years ago

According to the research, 43% of homes sold in a certain month and year were purchased by first-time buyers. A random sample

vovangra [49]

Answer Do it

Step-by-step explanation 165 divided by 100 =x times 43

4 0

3 years ago

Eva has £6.05 in her moneybox.

PIT_PIT [208]

Answer:

11 of 20p, 22 of 10p and 33 of 5p

Step-by-step explanation:

Eva has 20p, 10p and 5p coins, total of £6.05 = 605p

Let 20p=x, 10p=y, 5p=z

Then:

20x + 10y + 5z = 605
y : x = 2 : 1 ⇒ x= y/2
y : z = 2 : 3 ⇒ z= 3y/2

Rewriting the first equation considering next two:

10y + 10y + 7.5y = 605
27.5y = 605
y= 605/27.5
y= 22
x= y/2 = 22/2 = 11
z = 3y/2 = 3*11 = 33

Answer: 11 of 20p coins, 22 of 10p coins and 33 of 5p coins

3 0

3 years ago