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iris [78.8K]
3 years ago
11

The volume of a cube can be found using the equation V = s³, where V is the volume and s is the measure of one side of the cube.

Mathematics
2 answers:
Sphinxa [80]3 years ago
7 0

we know that

The volume of a cube is equal to

V=s^{3}

where

s is the length side of the cube

solve for s

s=\sqrt[3]{V} --------> equation 1

in this problem we have

V=2,560\ in^{3}

substitute the value of V in the equation 1

s=\sqrt[3]{2,560}\ in

therefore

<u>the answer is</u>

s=\sqrt[3]{2,560}\ in

zzz [600]3 years ago
7 0

Answer: Its s = 3/2560 in.

Step-by-step explanation:

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professor190 [17]

Given that Kimora’s cell phone company charges her $35 a month for phone service plus $.05 for each text message sent.

Kimora's cell phone bill for one month is $52.

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<u>The equation:</u>

Let x denote the number of text messages Kimora sent for one month.

Thus, the equation is given by

35+0.05x=52

Therefore, the equation for the number of text messages Kimora sent for one month is 35+0.05x=52

<u>Solving the equation:</u>

We need to solve the equation 35+0.05x=52

Subtracting both sides of the equation by 35, we get;

0.05x=17

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x=340

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3 0
3 years ago
What is 160% of 80kg
andre [41]

Answer:

128kg

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Pls help I will give points
s2008m [1.1K]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Given sin(u)= -7/25 and cos(v) = -4/5, what is the exact value of cos(u-v) if both angles are in quadrant 3
solmaris [256]

Given:

\sin (u)=-\dfrac{7}{25}

\cos (v)=-\dfrac{4}{5}

To find:

The exact value of cos(u-v) if both angles are in quadrant 3.

Solution:

In 3rd quadrant, cos and sin both trigonometric ratios are negative.

We have,

\sin (u)=-\dfrac{7}{25}

\cos (v)=-\dfrac{4}{5}

Now,

\cos (u)=-\sqrt{1-\sin^2 (u)}

\cos (u)=-\sqrt{1-(-\dfrac{7}{25})^2}

\cos (u)=-\sqrt{1-\dfrac{49}{625}}

\cos (u)=-\sqrt{\dfrac{625-49}{625}}

On further simplification, we get

\cos (u)=-\sqrt{\dfrac{576}{625}}

\cos (u)=-\dfrac{24}{25}

Similarly,

\sin (v)=-\sqrt{1-\cos^2 (v)}

\sin (v)=-\sqrt{1-(-\dfrac{4}{5})^2}

\sin (v)=-\sqrt{1-\dfrac{16}{25}}

\sin (v)=-\sqrt{\dfrac{25-16}{25}}

\sin (v)=-\sqrt{\dfrac{9}{25}}

\sin (v)=-\dfrac{3}{5}

Now,

\cos (u-v)=\cos u\cos v+\sin u\sin v

\cos (u-v)=\left(-\dfrac{24}{25}\right)\left(-\dfrac{4}{5}\right)+\left(-\dfrac{7}{25}\right)\left(-\dfrac{3}{25}\right)

\cos (u-v)=\dfrac{96}{625}+\dfrac{21}{625}

\cos (u-v)=\dfrac{1 17}{625}

Therefore, the value of cos (u-v) is 0.1872.

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