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Dmitry [639]
3 years ago
11

What is the answer to this problem

Mathematics
1 answer:
lyudmila [28]3 years ago
8 0

When two pentagons are congruent, then the corresponding angles and sides are equal (congruent).

As, Pentagon GDXLP\cong Pentagon ARKMV

Being congruent, the corresponding sides are equal(congruent).

So, \overline{GD} \cong \overline{AR} , \overline{DX} \cong \overline{RK} , \overline{XL} \cong \overline{KM} , \overline{LP} \cong \overline{MV} , \overline{GP} \cong \overline{AV} , \overline{GL} \cong \overline{AM} , \overline{DL} \cong \overline{RM} , \overline{DP} \cong \overline{RV} and \overline{XP} \cong \overline{KV}

Being Congruent, corresponding angles are also equal (congruent).

So, \angle G \cong \angle A , \angle D \cong \angle R , \angle X \cong \angle K , \angle L \cong \angle M , \angle P \cong \angle V

Therefore, Option 2 , 4 and 5 are correct.

That is,\angle X \cong \angle K

\overline{GP} \cong \overline{AV}

and \overline{PL} \cong \overline{VM}

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Answer:

Richard used 2\frac{1}{12}\ yd ^2 of fabric for his project.

Step-by-step explanation:

Given:

Total amount of fabric = 11\frac23\ yd^2

Now To convert a mixed fraction to an improper fraction, Multiply the whole number part by the fraction's denominator,  Add that to the numerator,Then write the result on top of the denominator.

11\frac23\ yd^2 can be Rewritten as \frac{35}{3}\ yd^2

Number of pieces fabric was cut = 4

Richard is given one of four pieces of equal-sized fabric.

Amount of fabric Richard was given = \frac14 \times \frac{35}{3}=\frac{35}{12}\ yd^2

Amount of fabric left with Richard = \frac56 \ yd^2

We need to find the amount of fabric Richards used for his project.

Solution:

Now we can say that;

amount of fabric Richards used for his project is equal to Amount of fabric Richard was given minus Amount of fabric left with Richard.

framing in equation form we get;

amount of fabric Richards used for his project = \frac{35}{12}-\frac56

Now we will make the denominator common using LCM we get;

amount of fabric Richards used for his project = \frac{35}{12}-\frac{5\times2}{6\times2} = \frac{35}{12}-\frac{10}{12}

Now Denominator is same so we will solve the numerator.

amount of fabric Richards used for his project  = \frac{35-10}{12}= \frac{25}{12}\ yds^2

\frac{25}{12}\ yds^2 can be rewritten as 2\frac{1}{12}\ yd ^2

Hence Richard used 2\frac{1}{12}\ yd ^2 of fabric for his project.

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3 years ago
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Step-by-step explanation:

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zalisa [80]

Answer:

k = 7

Step-by-step explanation:

Applying,

S = (y₂-y₁)/(x₂-x₁)................ Equation 1

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