Question

100 POINTSSS! ASAP ANSWEERR PLS

Answer 1

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = $\frac{FV-SV}{SV}*100$        (FV = final value, SV = starting value)

Percentage increase = $\frac{1.4214 - 0.7107}{0.7107}*100$

Percentage increase = $\frac{0.7107}{0.7107}*100$

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = $\frac{10,201-10,100}{10,100}*100$

                                                             = $\frac{101}{10,100}*100$

                                                             = 0.01 * 100

                                                             = 1 %

PC of product B from 2nd to 3rd year = $\frac{10,303.01-10,201}{10,201} *100$

                                                              = 1%

PC of product B from 3rd to 4th year $=\frac{10,406.04-10,303.01}{10,303.01}*100$

                                                              ≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

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