Question

PLZ HELP ASAP!!!!!!!,

Answer 1

The answer to your question is 10 seconds. I know this because:

distance divided by speed=time
let t=time
t=2*6(30/36)=10
t=10
So, it took Boris a total of 10 seconds to run up the out of service elevator.

Hope this helps!

Answer 2

Answer:10 sec

Step-by-step explanation:

Given

Boris can run up the escalator in 6 sec

Also he can run up the down escalator in 30 sec

i.e. He travel same distance either ways

Let the distance be x and v be the speed of boris and $v_0$ be the speed of escalator.

$x=6\times \left ( v+v_0\right )$----1

$x=30\times\left ( v-v_0\right )$----2

Equating 1 and 2

$5\left ( v-v_0\right )=v+v_0$

$5v-5v_0=v+v_0$

$v_0=\frac{2}{3}v$

substituting in 1

$x=6\times \left ( v+v\frac{2}{3}\right )$

$x=6\times v\frac{5}{3}=10v$

Thus form above equation we can say that it requires 10 sec for Boris to climb up in out of service escalator.