The length of the shortest side of the hexagon is; 41.833 inches
<h3>How to find the perimeter of a Polygon?</h3>
Let the length of the shortest side of the hexagon be x. Now, a hexagon has six sides and if the next side is 10 inches longer than the previous side, then the length of the six sides are;
x, x + 10, x + 20, x + 30, x + 40, x + 50
Perimeter is given as 401 inches. Thus;
x + x + 10 + x + 20 + x + 30 + x + 40 + x + 50 = 401
6x + 150 = 401
6x = 401 - 150
6x = 251
x = 251/6
x = 41.833 inches
Read more about Polygon Perimeter at; brainly.com/question/14490532
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The best thing to do is to rewrite the fractions as decimals
-2/3 is approx. equal to -0.6666667
So a little past half way (to the left) between -1 and 0
1 1/5 is 1.5 so that is right between 1 and 2
Hope this helps :)
Answer:
52,53,54
Step-by-step explanation:
x, x+1, x+2
2x+1=x+53
x+1=53
x=52
x+1=53
x+2=54
Answer: but I need the points sorri
A)
<span>|x + y = 5 </span>
<span>|2x - y = 7; </span>
<span>b) </span>
<span>|2x + y = 5 </span>
<span>|x - y = 2 </span>
<span>c) </span>
<span>|3x + y = 6 </span>
<span>|4x - 3y = -5 </span>
<span>d) </span>
<span>|1/(x - 1) = y - 3 </span>
<span>|x - y = -2 </span>
<span>e) </span>
<span>|(9x + 4y)/3 - (5x - 11)/2 = 13 - y </span>
<span>|13x - 7y = -8 </span>
<span>Answer: </span>c<span> and </span>e<span> has solution (1; 3)</span>
