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ivanzaharov [21]
3 years ago
7

Jean bought a bag of candy that contained red candies, green candies, and brown candies. Some candies are marked with a smile an

d others are not marked. The probabilities are displayed in the table below:
| Red |Green |Brown
Smile |0.100 | .300 | .10
No smile |0.200 | .150 | .15

If a random candy is chosen from this bag, what is the probability that the candy was red or had no smile?
Mathematics
2 answers:
lana66690 [7]3 years ago
6 0
                   | Red    |Green  | Brown   Total
<span>Smile         |0.100  | .300    | .10           0.50</span>
<span>No smile   |0.200  | .150    | .15            0.50
Total           0.30       0.45      0.25         1.00

The probability of choosing red candy is 0.10
The probability of choosing no smile candy is 0.50

The probability of choosing red or no smile = 0.10 + 0.50 = 0.60

I did not use 0.30 as the probability of red because it included the no smile candy. It should only be red candy that has a smile.</span>
gulaghasi [49]3 years ago
4 0

Answer: .60. Just took the quiz

Step-by-step explanation:

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Let x be the cost of 1 adult ticket

Let y be the cost of 1 child ticket

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Cost of 9 child tickets = 9y

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