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3 years ago

How do you do this question?

Mathematics

1 answer:

max2010maxim [7]3 years ago

6 0

Answer:

∫₁⁵ 2t (t² + t³) dt

Step-by-step explanation:

The area is ∫ₓ₁ˣ² y dx. To parameterize, replace x₁ and x₂ with t₁ and t₂. Replace y = f(x) with y = f(t), and replace dx with (dx/dt) dt.

x = 5 + t², so dx = 2t dt.

∫₁⁵ (t² + t³) (2t dt)

∫₁⁵ 2t (t² + t³) dt

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Construct a quadrilateral abcd in which. ab=4 cm and ad=5cm ,Angle A=60°.Angle B=90°and Angle D=90°

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2 years ago

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A gardener has a container with 6 3/5 ounces of liquid plant fertilizer. The gardener uses 2 1/2 ounces on a flower garden. How

docker41 [41]

Answer:

4 1/10 ounces of Liquid plant fertilizer left

Step-by-step explanation:

Total quantity of Liquid plant fertilizer=6 3/5 ounces

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6-2 3/5 - 1/2

4 (6-5) / 10

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3 years ago

Integration: How would I get to this answer?

Scrat [10]

Given that $y$ attains a maximum at $x=1$ , it follows that $y'=0$ at that same point. So integrating once gives

$\displaystyle\int\frac{\mathrm d^2y}{\mathrm dx^2}\,\mathrm dx=\int-8x\,\mathrm dx$
$\dfrac{\mathrm dy}{\mathrm dx}=-4x^2+C_1$
$\implies -4(1)^2+C_1=0\implies C_1=4$

and so the first derivative is $y'=-4x^2+4$ .

Integrating again, you get

$\displaystyle\int\frac{\mathrm dy}{\mathrm dx}\,\mathrm dx=\int(-4x^2+4)\,\mathrm dx$
$y=-\dfrac43x^3+4x+C_2$

You know that this curve passes through the point (2, -1), which means when $x=2$ , you have $y=-1$ :

$-1=-\dfrac43(2)^3+4(2)+C_2$
$\implies C_2=\dfrac53$

and so

$y=-\dfrac43x^3+4x+\dfrac53$