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DIA [1.3K]
4 years ago
11

How do you do this question?

Mathematics
1 answer:
max2010maxim [7]4 years ago
6 0

Answer:

∫₁⁵ 2t (t² + t³) dt

Step-by-step explanation:

The area is ∫ₓ₁ˣ² y dx.  To parameterize, replace x₁ and x₂ with t₁ and t₂.  Replace y = f(x) with y = f(t), and replace dx with (dx/dt) dt.

x = 5 + t², so dx = 2t dt.

∫₁⁵ (t² + t³) (2t dt)

∫₁⁵ 2t (t² + t³) dt

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Find the distance beyween S(6, -3) and T (7, -2)
s344n2d4d5 [400]

Answer:

d=\sqrt{2}

Step-by-step explanation:

Distance Formula: d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Simply plug in your 2 coordinates into the distance formula to find distance <em>d</em>:d=\sqrt{(7-6)^2+(-2-(-3))^2}

d=\sqrt{(1)^2+(-2+3)^2}

d=\sqrt{1+(1)^2}

d=\sqrt{1+1}

d=\sqrt{2}

3 0
3 years ago
Read 2 more answers
A: (0, –t)<br><br> B: (0, r)<br><br> C: (t, 0)<br><br> D: (–r, 0)
adell [148]
D should be the right answer
7 0
3 years ago
-1+(-8) is how many units away from 4 on the number line
yKpoI14uk [10]

Answer:

13 units

Step-by-step explanation:

-1 + (-8) = -9

|-9| = 9 + 4 = 13

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Hopefully this helps you :)

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5 0
3 years ago
3/5 of a group of children were girls. If there were 24 girls, how many children were there in the group
VLD [36.1K]

3/5  of the group = 24

1/5  of the group = 8

The group = 5 x 8  =  40 .
7 0
3 years ago
The dimensions of a rectangle box are consecutive integers. If the box has volume of 13,800 cubic centimeters, what are its dime
dezoksy [38]

If the dimensions were all the same number ... the box was a cube ...
then each dimension would be  (the cube root of 13,800) cm.

         ∛13,800 = 23.986... (rounded)

so the place to look is around 23 .

(22 x 23 x 24)  =  12,144     <==  too small; go up one integer

(23 x 24 x 25)  =  13,800     <==  Eureka !    

The consecutive integers are  23,  24,  and  25 .

4 0
3 years ago
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