Answer:

Step-by-step explanation:
We are given that


y(0)=0
y'(0)=1
By comparing with

We get


q(x)=0
p(x),q(x) and g(x) are continuous for all real values of x except 3.
Interval on which p(x),q(x) and g(x) are continuous
and (3,
By unique existence theorem
Largest interval which contains 0=
Hence, the larges interval on which includes x=0 for which given initial value problem has unique solution=
9514 1404 393
Answer:
8x -3y = 33
Step-by-step explanation:
Multiply by 3 to eliminate the fraction. Then rearrange to standard form.
y +7 = 2/3(4x -6) . . . . . . . given
3(y +7) = 2(4x -6) . . . . . . . multiply by 3
3y +21 = 8x -12 . . . . . . . . eliminate parentheses
33 = 8x -3y . . . . . . . . . . add 12-3y to both sides
8x -3y = 33 . . . . . . . . . swap sides to put into standard form
_____
Standard form has mutually prime integer coefficients, the leading one being positive.
Answer:
2
Step-by-step explanation:
|-6+8|
Add/subtract the numbers: -6 + 8 = 2
= |2|
Apply the absolute value rule: |a| = a, a ≥ 0
= 2
Answer:
the answer is 85.33π cm
Step-by-step explanation:
I think that the answer is A.