let me edit your question as:
Which two equations are true?
<u>Eq1:</u>
(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)
<u>Eq2:</u>
6.6×10−10(6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.7×103)
<u>Eq3:</u>
2.7×103(7.5×106)−(2.5×106)=5×100
Answer:
No one is true
Step-by-step explanation:
let's check each equation, if the values on both sides (left and right side) are equal then the equation is true otherwise false.
Using PEMDAS rule we are simplifying the equations as;
<u>Eq1:</u>

<u>Eq2:</u>
<u></u>
<u></u>
<u>Eq3:</u>

<u>we observed that none of the equation has two same values on both sides thus none of the three equations is true.</u>
<u>Also, no value of Eq1, Eq2 or Eq3 are same thus none of the equation is true</u>
Answer:
y = 108°
Step-by-step explanation:
Since AB and CD are parallel lines, then
3x - 12 and 2x + 16 are corresponding angles and congruent, thus
3x - 12 = 2x + 16 ( subtract 2x from both sides )
x - 12 = 16 ( add 12 to both sides )
x = 28
Thus
3x - 12 = 3(28) - 12 = 84 - 12 = 72°
y and 3x - 12 are adjacent angles and supplementary, thus
y = 180° - 72° = 108°
I factor it because you can't simplify
2x-8=2(x-4)
X^2+5x+4=(x+1)(x+4)
X^2-16=(x-4)(x+4)
X^2+8x+16=(x+4)(x+4)