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ANTONII [103]
3 years ago
5

Ok, I was put in a class higher than my level, plz explain how to get the angle too, thx!

Mathematics
2 answers:
erica [24]3 years ago
6 0

Answer:

D

Step-by-step explanation:

The angle is obviously smaller than 45 degrees so that eliminates A and B, and 15 times 3 does not equal 27, so that eliminates C. that leaves D, 3 times 9 equals 27 degrees.

dlinn [17]3 years ago
4 0

Answer:

d

Step-by-step explanation:

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(copy and paste for picture)
NemiM [27]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
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there are 15 black marbles and 10 white marbles in a bag. If you pick a marble from the bag without looking, what are your chanc
satela [25.4K]

Answer: 40%

Step-by-step explanation:

6 0
4 years ago
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A fluid moves through a tube of length 1 meter and radius r=0.006±0.00025 meters under a pressure p=4⋅105±2000 pascals, at a rat
iris [78.8K]

Answer:

Maximum error for viscosity is 17.14%

Step-by-step explanation:

We know that everything is changing with respect to the time, "r" is changing with respect to the time, and also "p" just "v" will not change with the time according to the information given, so we can find the implicit derivative with respect to the time, and since

n = (\frac{\pi}{8}) (\frac{pr^4}{v})\\

The implicit derivative with respect to the time would be

\frac{dn}{dt}  = \frac{\pi}{8} ( \frac{r^4}{v} \frac{dp}{dt}  + \frac{4pr^3}{v}\frac{dr}{dt} )

If we multiply everything by    dt   we get  

dn  = \frac{\pi}{8} ( \frac{r^4}{v} dp  + \frac{4pr^3}{v}  dr})

Remember that  the error is given by   \frac{dn}{n}   therefore doing some algebra we get that

\frac{dn}{n}  =    4 \frac{dr}{r}  +  \frac{dp}{p}

Since,    r = 0.006   ,   dr = 0.00025 ,  p = 4*105   ,   dp = 2000  we get that

\frac{dn}{n} = 0.1714

Which means that  the maximum error for viscosity is 17.14%.  

5 0
3 years ago
A school is 16km due west of a school q.<br>What is the bearing of q from p?<br><br><br>​
Arada [10]

Answer:

16 km due west

Step-by-step explanation:

The bearing of the school p from school q is 16 km due west.

To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.

Since p is directly west of q, then it implies that q must be directly east of p.

We now know the direction.

Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.

Hence, the bearing of q from p is 16 km due west.

3 0
3 years ago
james scored 300 runs in cricket. he requires 900 runs to qualify for league MVP contention. he scores 50 runs during the averag
Serhud [2]
He would need to play 12 average scoring games.
900 (goal) - 300 (has) = 600
and 600/50 is 12 
hope this helps :)
5 0
4 years ago
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