Question

Simplify 4 times square root 24 minus 4 square root 8 plus square root of 98.

Answer 1

$4*\sqrt{24}-4\sqrt{8}+\sqrt{98}\\\\4\sqrt{4*6}-4\sqrt{4*2}+\sqrt{49*2}\\\\4\sqrt{4}\sqrt{6}-4\sqrt{4}\sqrt{2}+\sqrt{49}\sqrt{2}\\\\4*2*\sqrt{6}-4*2*\sqrt{2}+7*\sqrt{2}\\\\8\sqrt{6}-8\sqrt{2}+7\sqrt{2}\\\\\\8\sqrt{6}-\sqrt{2}$

Answer 2

Answer:

$8 *\sqrt{ 6}$ - 1 $\sqrt{2}$.

Step-by-step explanation:

Given : 4 times square root 24 minus 4 square root 8 plus square root of 98.

To find : Simplify .

Solution : We have given statement .

According to questions :

4 times square root 24 = $4 *\sqrt{24}$.

4 square root 8 =  $4 *\sqrt{8}$.

Square root of 98 =  $\sqrt{98}$.

Then

$4 *\sqrt{24}$ -  $4 *\sqrt{8}$ +  $\sqrt{98}$.

We can write 24 as 4 *6 and 8 as 4 *2 and 98 as 49 *2

$4 *\sqrt{4 * 6}$ -  $4 *\sqrt{4 *2}$ +  $\sqrt{49 * 2}$.

On solving square root.

$4 * 2*\sqrt{ 6}$ -  $4 * 2 *\sqrt{2}$ + 7* $\sqrt{2}$.

$8 *\sqrt{ 6}$ -  $8*\sqrt{2}$ + 7* $\sqrt{2}$.

$8 *\sqrt{ 6}$ - ( 8 - 7) $\sqrt{2}$.

$8 *\sqrt{ 6}$ - 1 $\sqrt{2}$.

Therefore, $8 *\sqrt{ 6}$ - 1 $\sqrt{2}$.