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3 years ago

which graph represents the solution set for the system 2x+5≤9 and 3x+5y≤9 Graph A. Graph B. Graph C. Graph D.

Mathematics

1 answer:

Likurg_2 [28]3 years ago

6 0

See attached graph

Hope that helps.

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Iam really lost on this one please need help

mafiozo [28]

I would say -13 because y = - 10 - 3 would mean that what ever -10 minus 3 equals is what y equals and -10 - 3 is -13

3 0

3 years ago

The graph of the function, B(x), is shown below. Determine the following values for the function:

Softa [21]

Answer:

$B(-1) = 1\\\\B(3) = 0\\\\B(1) =2$

Step-by-step explanation:

By definition, a relation is a function if each input value has one and only one output value.

The input values are the x-values and the output values are the y-values.

Given:

$B(-1),B(3)$ and $B(1)$

We can identify that we need to find the output values of these input values:

$x=-1\\x=3\\x=1$

Observe in the graph attached that:

When $x=-1,\ y=1$

When $x=3,\ y=0$

When $x=1,\ y=2$

Therefore:

$B(-1) = 1\\\\B(3) = 0\\\\B(1) =2$

7 0

3 years ago

20 POINTS PLEASE SOMEONE ANSWER What is the equation of the line with m = 3 and b = 8.25? a. y = 3x – 8.25 b. y = 3x 8.25 c. y =

konstantin123 [22]

Answer:

Equation of the line with m=3 and b = 8.25 is y=3 x+8.25

Step-by-step explanation:

m = 3 and b = 8.25

To get equation of line we use y=mx+b

Where m represents the slope = 3

b represents the y intercept = 8.25

Plug in the values in y=mx+b

y= 3x + 8.25

Equation of the line with m=3 and b = 8.25 is y=3 x+8.25

5 0

3 years ago

Read 2 more answers

Simplify the expression<br><br>cot^2x - cot^2x cos^2x

andrew-mc [135]

Cot^2x - cot^2x cos^2x
= cot^2x - {(cot^2x)(cos^2x)}
= cot^2x { 1 - cos^2x }
= cot^2x { sin^2x }
= (cos^2x/sin^2x) { sin^2x }
= cos^2x

8 0

3 years ago

Determine the equation of the linear graph that passes through (-2,3) and (4,6). State your answer in the

Lena [83]

The linear equation is y = 4 + 0.5x

<h3>How to determine the equation?</h3>

The points are given as: (-2,3) and (4,6)

The equation is then calculated using:

$y = \frac{y_2 -y_1}{x_2 -x_1} *(x - x_1) + y_1$

Substitute the known values

$y = \frac{6-3}{4+2} *(x+2) + 3$

Evaluate

y = 0.5 *(x+2) + 3

Expand

y = 0.5x + 1 + 3

Evaluate the sum

y = 0.5x + 4

Rewrite as:

y = 4 + 0.5x

Hence, the equation is y = 4 + 0.5x

Read more about linear equations at:

brainly.com/question/14323743

#SPJ1

3 0

2 years ago