Answer:
The solution code is written in Python
- def largerThanN(myList, n):
- output = ""
-
- for x in myList:
- if(x > n):
- output += str(x) + " "
-
- print(output)
-
- l = [5, 12, 11, 4, 56, 32]
- n = 15
- largerThanN(l, n)
Explanation:
Firstly, create a function largerThanN that accepts two arguments, a list (myList) and a number (n) (Line 1).
Next, create a output variable to hold the string of numbers in the list that are greater than the input number n (Line 2).
Create a for loop to traverse through each number in the list and then check if the current x is bigger than n. If so concatenate the x to output string along with a single space " " (Line 4 -6)
After the loop, print the output string (Line 8)
We test the function by using a sample list and n = 15 (Line 10 - 12). The program will display 56 32 .
A. journals
Medical journals, or scientific journals are always a good source for information for something like this!
Answer:
Following are the program in the C++ Programming Language.
//set header file or namespace
#include <iostream>
using namespace std;
//define main function
int main() {
//set integer type array with indexing 10
int a[10];
//set integer type variable to 1
int i=1;
//set element in 1st index
a[0]=17;
//set element in last index
a[9]=29;
//set while loop for the remaining elements
while(i<9)
{
//set -1 in the remaining elements
a[i]=-1;
i++;
}
//set for loop to print array
for ( int j = 0; j < 10; j++ ) {
cout << a[j]<<endl;
}
}
<u>Output:</u>
17
-1
-1
-1
-1
-1
-1
-1
-1
29
Explanation:
In the following program, we define the main function "main()" and inside it.
- Set an integer type array element "a[]" with index value 10.
- Set integer data type variable "i" initialize to 1.
- Set elements in the first and last place in the array.
- Set the while loop to initialize elements for the remaining place.
- Set the for loop to print the array elements.
Answer:
Don’t know lol but look it up on g00gle and she will have the answr
Explanation:
