Answer:
a. The possible dimensions of the total area are;
The width of the total area is (2·x + 8) inches
The length of the total area is (2·x + 10) inches
b. The dimensions of the photos are as follows;
The length of the photos are 10 inches
The width of the photos are 8 inches
Step-by-step explanation:
a. Given that the area, A = 4·x² + 36·x + 80
We get;
A = 4 × (x² + 9·x + 20) = 4 × (x + 4) × (x + 5) = (2·x + 8)·(2·x + 10)
Therefore, the possible dimensions of the total area (photo + mat) are;
The width of the total area (photo + mat) = (2·x + 8) in.
The length of the total area (photo + mat) = (2·x + 10) in.
b. The dimensions of the photos alone are shorter than the dimensions of the photo and mat combined by 2·x each
Therefore, we have the dimensions of the photos are as follows;
The length of the photo = (2·x + 10) in. - 2·x in. = 10 in.
The width of the photos = (2·x + 8) in. - 2·x in. = 8 in.
Root (7^2 + 7^2) = 7root2
It C
There are 1760 yards in one mile and the rink is 250 yard in perimeter.
This means 3 miles is 5280 yards.
If Sam has already gone around the whole rink 6 times, that means he was traveled a total of 1500 yards.
Sam has 3780 more yards to travel 3 miles.
This means he needs to do 15.12 more laps around the rink. Or 16 if you are rounding.
Hope this helps! :)
Answer:
-15/4 or -3.75
Step-by-step explanation:
Answer:
9
Step-by-step explanation:
you divide 468 by 52
468/52 = 9
