For a function to begin to qualify as differentiable, it would need to be continuous, and to that end you would require that 
is such that
Obviously, both limits are 0, so 
is indeed continuous at 
.
Now, for to be differentiable everywhere, its derivative 
must be continuous over its domain. So take the derivative, noting that we can't really say anything about the endpoints of the given intervals:
and at this time, we don't know what's going on at , so we omit that case. We want to be continuous, so we require that
from which it follows that 
.
Hi there
14000=-2000t+20000
Solve for t to find the age of the car
2000t=20000-14000
2000t=6000
T=6000/2000
T=3 years
Hope it helps
Answer:
B.
Step-by-step explanation:
21 X 2 = 42
42-7 = 35
35 + 21 = 56
So from solving the problem, we know that the answer must equal -28.
When you solve all of the given options, we find that the only one that does equal -28 would be A.) (-6)(4) + (-6)(2/3).
When I doubt, solve it out. I hope I could help!
