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3 years ago

If you travel 40 miles east and then turn around and drive 12 miles west, the displacement is?

2 answers:

6 0

To find how far east we drove (This is the displacement), we simple subtract 12 from 40.
An easy way to do this in your head is to round 12 down to 10, subtract 10 from 40, then subtract the remaining 2. This should result in an answer showing that you drove 28 miles east.

Sauron [17]3 years ago

6 0

Answer:

The displacement is 28 miles.

Explanation :

Given that,

Distance to east = 40 miles

Distance to west = 12 miles

We need to calculate the displacement

Using formula of displacement

$D = X_{2}-X_{1}$

Where, D = displacement

X₁= Initial distance to east

X₂ = final distance to west

Put the value into the formula

$D=12-40$

$D = -28\ miles$

Negative sign show the direction of east

Hence, The displacement is 28 miles.

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Blue light of wavelength 450 nm passes through a diffraction grating with a slit spacing of 0.001 mm and makes an interference p

IceJOKER [234]

Answer:

5 fringes option C

Explanation:

Given:

- The wavelength of blue light λ = 450 nm

- The split spacing d = 0.001 mm

Find:

How many bright fringes will be seen?

Solution:

- The relationship between the wavelength of the incident light, grating and number of bright fringes seen on a screen is derived by Young's experiment as follows:

sin(Q) = n* λ / d

Where, n is the order of bright fringe. n = 0, 1, 2, 3, ....

- We need to compute the maximum number of fringes that can be observed with the given condition and setup. Hence we will maximize our expression above by approximating sin(Q).

sin(Q_max) = 1

Q_max = 90 degree

- Hence, we have:

n = d / λ

- plug values in n = 0.001 *10^-3 / 450*10^-9

n = 2.222

- Since n order number can only be an integer we will round down our number to n = 2.

- Hence, we will see a pair of bright fringes on each side of central order fringe.

- Total number of fringes = 2*2 + 1 = 5 fringes is total ... Hence, option C

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3 years ago

Cloudy days tend to have a greater range of temperatures than clear days. True or false?

emmasim [6.3K]

Answer:

true

Explanation:

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3 years ago

Read 2 more answers

Contrast the movement of charges in a series circuit and in a parallel circuit.

inessss [21]

In a series circuit, there is only one possible path from one battery
terminal, through the circuit, to the other battery terminal. All of the
current that leaves one side of the battery travels exactly the same
path to the other side of the battery. There's never any point in the
circuit where the current has a choice of which way to go.

In a parallel circuit, there are different possible paths. On its way
through the circuit, the current comes to a point where it has a
choice of going this way or that way. What happens at that point
is that the current splits up ... part of it goes this way, and the rest
of it goes that way, and it all joins up together again somewhere
else in the circuit.

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3 years ago

What systems of the body are involved in preparing and eating a sandwich

jek_recluse [69]

<span>The systems of the body involved in preparing and eating a sandwich are :
</span>The skeletal, muscular, and digestive system. They are all directly involved in eating and preparing a sandwich.

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3 years ago

On the earth, when an astronaut throws a 0.250-kg stone vertically upward, it returns to his hand a time T later. On planet X he

Pachacha [2.7K]

Answer:

d) g/2

Explanation:

We need to use one of Newton's equations of motion to find the position of the stone at any time t.

x(t) = x₀(t) + ut - ¹/₂at²

Where

x₀(t) = initial position of the stone.

x(t) - x₀(t) = distance traveled by the stone at any time.

u = initial velocity of the stone

a = acceleration of the stone

t = time taken

On both planets, before the stone was thrown by the astronaut, x = 0 and t = 0.

=> 0 = x₀(t)

=> x₀(t) = 0

On earth, when the stone returns into the hand of the astronaut at time T on earth, x = 0.

=> 0 = 0 + uT - ¹/₂gT² (a = g)

=> uT = ¹/₂gT²

=> g = 2u/T

On planet X, when the stone returns into the hand of the astronaut, time = 2T , x = 0.

=> 0 = 0 + u(2T) - ¹/₂a(2T)²

=> 2uT = 2aT²

=> a = u/T

By comparing we see that a = g/2.

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4 years ago