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3 years ago

8

Which option is a microscopic property that helps determine whether or not two substances will dissolve with each other? (1 poin

t)
volume

polarity

molecular mass

state of matter

1 answer:

Bumek [7]3 years ago

8 0

Answer:

The answer is polarity

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In an experiment, a variable, position-dependent force F(x)F(x) is exerted on a block of mass 1.0kg1.0kg that is moving on a hor

leonid [27]

Answer:

The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).

(C) is correct option.

Explanation:

Given that,

Mass of block = 1.0 kg

Dependent force = F(x)

Frictional force = F(f)

Suppose, the following information would students need to test the hypothesis,

(A) The function F(x) for 0 < x < 5 and the value of F(f).

(B) The function a(t) for the time interval of travel and the value of F(f).

(C) The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).

(D) The function a(t) for the time interval of travel, the time it takes the block to move 5 m, and the value of F(f).

(E) The block's initial velocity, the time it takes the block to move 5 m, and the value of F(f).

We know that,

The work done by a force is given by,

$W=\int_{x_{0}}^{x_{f}}{F(x)\ dx}$ .....(I)

Where, $F(x)$ = net force

We know, the net force is the sum of forces.

So, $\sum{F}=ma$

According to question,

We have two forces F(x) and F(f)

So, the sum of these forces are

$F(x)+(-F(f))=ma$

Here, frictional force is negative because F(f) acts against the F(x)

Now put the value in equation (I)

$W=\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}$

We need to find the value of $\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}$

Using newton's second law

$\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\int_{x_{0}}^{x_{f}}{ma\ dx}$ ...(II)

We know that,

Acceleration is rate of change of velocity.

$a=\dfrac{dv}{dt}$

Put the value of a in equation (II)

$\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\int_{x_{0}}^{x_{f}}{m\dfrac{dv}{dt}dx}$

$\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\int_{v_{0}}^{v_{f}}{mv\ dv}$

$\int_{x_{0}}^{x_{f}}{(F(x)-F(f))dx}=\dfrac{mv_{f}^2}{2}+\dfrac{mv_{0}^2}{2}$

Now, the work done by the net force on the block is,

$W=\dfrac{mv_{f}^2}{2}+\dfrac{mv_{0}^2}{2}$

The work done by the net force on the block is equal to the change in kinetic energy of the block.

Hence, The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F(f).

(C) is correct option.

7 0

3 years ago

Write the function of alcohol in a alcohol thermometer.

Serhud [2]

Answer:

Ethanol-filled thermometers are used in preference to mercury for meteorological measurements of minimum temperatures and can be used down to −70 °C (−94 °F). The physical limitation of the ability of a thermometer to measure low temperature is the freezing point of the liquid used.

8 0

3 years ago

How are stars important to the Milky Way

Elza [17]

Stars are a source of light and heat. They recycle all the matter, gas, and dust and process them into new material. They were created as a major driving force of evolution of the universe.

6 0

3 years ago

Read 2 more answers

The orbital motion of Earth around the Sun leads to an observable parallax effect on the nearest stars. For each star listed, ca

Murrr4er [49]

Answer:

Following are the answer to this question:

Explanation:

Formula:

$D(PC) =\frac{1}{parallax}\\\\D(av)=D(PC) \times 20.626\ J$

Calculating point A:

when the value is $0.38$

$\to 0.38 \toD(PC)= \frac{1}{0.38}\\\\$

$=2.632$

$\to D(a.v) = \frac{1}{0.38} \times 206265\\$

$=542,802.6$

Calculating point B:

when the value is $0.75$

$\to D(PC)=\frac{1}{0.75}$

$=1.33$

$\to D(a.v) = \frac{1}{0.75} \times 206265\\$

$=275,020$

Calculating point C:

when the value is $0.28$

$\to D(PC)=\frac{1}{0.28}$

$=3.571$

$\to D(a.v) = \frac{1}{0.28} \times 206265\\$

$=736660.7$

Calculating point D:

when the value is $0.42$

$\to D(PC)=\frac{1}{0.42}$

$=2.38$

$\to D(a.v) = \frac{1}{0.42} \times 206265\\$

$=490910.7$

Calculating point E:

when the value is $0.31$

$\to D(PC)=\frac{1}{0.31}$

$=3.226$

$\to D(a.v) = \frac{1}{0.31} \times 206265\\$

$=665370.97$

6 0

3 years ago

What average force is needed to accelerate a 7.00-gram pellet from rest to 155 m/s over a distance of 0.600 m along the barrel o

leonid [27]

Answer: The force needed is 140.22 Newtons.

Explanation:

The key assumption in this problem is that the acceleration is constant along the path of the barrel bringing the pellet from velocity 0 to 155 m/s. This means the velocity is linearly increasing in time.

The force exerted on the pellet is

F = m a

In order to calculate the acceleration, given the displacement d,

$d = \frac{1}{2}at^2\implies a=\frac{2d}{t^2}$

we will need to determine the time t it took for the pellet to make the distance through the barrel of 0.6m. That time can be determined using the average velocity of the pellet while traveling through the barrel. Since the velocity is a linear function of time, as mentioned above, the average is easy to calculate as:

$\overline{v}=\frac{1}{2}(v_{end}-v_{start})=\frac{1}{2}(155-0)\frac{m}{s}=77.5\frac{m}{s}$

This value can be used to determine the time for the pellet through the barrel:

$t = \frac{d}{\overline{v}}=\frac{0.6m}{77.5\frac{m}{s}}\approx0.00774s$

Finally, we can use the above to calculate the force:

$F = ma = m\frac{2d}{t^2} = 0.007kg\cdot \frac{2\cdot 0.6 m}{0.00774^2 s^2}\approx 140.22N$

8 0

3 years ago