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4 years ago

C²+5c-24=0 cant figure out how to solve this

Mathematics

2 answers:

Bumek [7]4 years ago

5 0

Move the 24 to the other side and that's the farthest it simplifies

frosja888 [35]4 years ago

4 0

Just solve the quadratic, you need to figure out what value you can use to FOIL and get c^2+5c-24=0. so you need to figure out what values you can add together to get 5 and multiply together to get -24 so try (c+8)(c-3) here 8 and 3 make sense since 8-3 = 5 and 8*-3=-24 so the answer is (c+8)(c-3).

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Justin runs each lap in 8 minutes. He will run at least 6 laps today. What are the possible numbers of minutes he will run today

IgorC [24]

Answer:

48 minutes

Answer:

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2 years ago

Subtract the following complex numbers:<br> (4 + 4i) - (13 + 17i)

lesya [120]

Step-by-step explanation:

Your problem → (4 + 4i) - (13 + 17i)

(4i+4)-(17i+13)

=4i+4-17i-13

=4i-17i+4-13

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3 years ago

Find the area of each parallelogram. What is the relationship between the areas?

castortr0y [4]

Answer:

Area of parallelogram is given by:

$A = bh$

where b is the base and h is the height of parallelogram.

In parallelogram TQRS.

Coordinate of TQRS are;

T(8, 16), Q(4, 4), R(16, 4) and S(20, 16)

Coordinate of T'Q'R'S' are;

T'(2, 4), Q'(1, 1), R'(4, 1) and S'(5, 4)

Find the length of QR and PT:

Using distance(D) formula:

$D = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$QR = \sqrt{(4-16)^2+(4-4)^2} =\sqrt{(-12)^2+0}= \sqrt{144}= 12$ units

Similarly;

For PT:

From the graph:

P(8, 4) and T(8, 16), then

$PT = \sqrt{(8-8)^2+(4-16)^2} =\sqrt{(-0)^2+(-12)^2}= \sqrt{144}= 12$ units

In parallelogram TQRS

PT represents the height and QR represents the base of the parallelogram respectively.

then;

Area of parallelogram TQRS = $QR \cdot PT$

⇒Area of parallelogram TQRS = $12 \cdot 12 = 144$ unit square.

Now, in parallelogram T'Q'R'S'

Q'R' represents the base and P'T' represents the height of the parallelogram respectively.

here, P'(2, 1)

Find the length of Q'R' and P'T':

$Q'R' = \sqrt{(1-4)^2+(1-1)^2} =\sqrt{(-3)^2+0}= \sqrt{9}= 3$ units

$P'T' = \sqrt{(2-2)^2+(1-4)^2} =\sqrt{(-0)^2+(-3)^2}= \sqrt{9}= 3$ units

Then;

Area of parallelogram T'Q'R'S' = $Q'R' \cdot P'T'$

Area of parallelogram T'Q'R'S' = $9 \cdot 9= 81$ unit square.

Now, we have to find the relationship between the areas.

$\frac{\text{Area of parallelogram TQRS}}{\text{Area of parallelogram T'Q'R'S'}} = \frac{144}{81}$

then;

the relationship between the areas of TQRS and T'Q'R'S' is:

$\text{Area of parallelogram TQRS} = \frac{144}{81} \cdot {\text{Area of parallelogram T'Q'R'S'}$

7 0

3 years ago

48% of their readers own a particular make of car. A marketing executive wants to test the claim that the percentage is actually

oksian1 [2.3K]

Answer:

There is no sufficient evidence to support the executive claim

Step-by-step explanation:

From the question we are told that

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The sample proportion is $\r p = 0.45$

The sample size is $n = 300$

The level of significance is $\alpha = 0.02$

The null hypothesis is $H_o : p= 0.48$

The alternative hypothesis is $H_a : p \ne 0.48$

Generally the test statistics is mathematically evaluated as

$t = \frac{\r p - p }{ \sqrt{ \frac{p(1 - p )}{n} } }$

=> $t = \frac{0.45 - 0.48 }{ \sqrt{ \frac{0.48 (1 - 0.48 )}{300} } }$

=> $t = -1.04$

The p-value is mathematically represented as

$p-value = 2P(z > |-1.04|)$

Form the z-table

$P(z > |-1.04|) = 0.15$

=> $p-value = 2 * 0.15$

=> $p-value = 0.3$

Given that $p-value > \alpha$ we fail to reject the null hypothesis

Hence we can conclude that there is no sufficient evidence to support the executive claim

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3 years ago

Three friends earned more than $200 washing cars they pay their parents $20 for supplies and divided the rest of the money equal

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3 years ago

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