Answer:
6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.
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Answer:
5 units
Step-by-step explanation:
If DG, EG and FG are perpendicular bisectors of the sides of triangle ABC, then point G is the circumcenter of the triangle ABC and
BG = AG = CG as radii of the circumcirle.
Consider right triangle BEG. By the Pythagorean theorem,
This gives us that
AG = BG = 5 units
Because HI and JK are parallel, that makes their angles congruent. So angle K equals angle I
So the interior angles of a triangle add up to 180°
So, Angle I + angle H + angle x =180°
60°+56°+x°=180°
116°+x°=180°
X=180-116
X=64°
We loveeeeeee the earth it is our planet
