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OlgaM077 [116]
2 years ago
12

Find the area of a regular octagon with

Mathematics
1 answer:
vodka [1.7K]2 years ago
5 0

Answer:

Step-by-step explanation:

Area=2(1+\sqrt{2})8²

       =309.0(round to nearest tenth)

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Wesley runs 10 kilometers every day. He runs 6 days per week for 50 minutes per day.
statuscvo [17]

Answer:

don't know maybe 60

Step-by-step explanation:

Idk

8 0
3 years ago
Help on this one question please!!
Mandarinka [93]
The correct answer is B.)
5 0
3 years ago
Which ordered pair is a solution of this<br> equation?<br> -3x + 7y - 6<br> =
Mumz [18]

Answer:

There are actually an infinite number of ordered pairs that will satisfy the equation y=3x+7 including (-1,4), (0,7) and (1, 10).

Step-by-step explanation:

5 0
2 years ago
What are the intercepts of 2x + 3y – 6z = 30?
ycow [4]

Intercept of equation 2x + 3y - 6z = 30 is (15, 0, 0) , (0, 10, 0) and (0, 0, -5)

<h3><u>Solution:</u></h3>

Given equation is:

2x + 3y - 6z = 30

We have to find the intercepts

Intercept are the point where equations cut the x- axis, y- axis and z- axis.

<em><u>Thus, at x- axis :</u></em>

y and z both are zero

So substitute y = 0 and z = 0 in given equation

2x + 3(0) - 6(0) = 30

2x = 30

x = 15

<h3>Thus the intercept is (15, 0, 0)</h3>

<em><u>Thus at y - axis:</u></em>

x and z both are zero

So substitute x = 0 and z = 0 in given equation

2(0) + 3y -6(0) = 30

0 + 3y + 0 = 30

3y = 30

y = 10

<h3>Thus the intercept is (0, 10, 0)</h3>

<em><u>Thus at z - axis:</u></em>

x and y are both zero

So substitute x = 0 and y = 0 in given equation

2(0) + 3(0) - 6z = 30

-6z = 30

z = -5

<h3>Thus the intercept is (0, 0, -5)</h3>

Thus, intercept of equation 2x + 3y - 6z = 30 is (15,0,0) ,(0,10,0) and (0,0,-5)

6 0
3 years ago
Find the four rational numbers and irrational numbers between 2/5 and 5/6
Savatey [412]
The four?

Of course there are an infinite number of rationals between any two different real numbers, as well as an even bigger infinite number of irrationals.

The average will be between the numbers:

\frac 1 2 (\frac 2 5 + \frac 5 6) = \dfrac{37}{60}

That's a lot of work to get a number in between.  We can just see

\frac 1 2
is between the two numbers.

The mediant, or freshman addition, will always be in between:

\dfrac{2 + 5}{5 + 6} = \dfrac{7}{11}

2/5=.4 and 5/6 is about .83, so

.6 = \frac{6}{10}

is in between as is .7, .41, .530940394 and as many rationals as we care to generate.

To get irrationals we could just add a teeny irrational to the ones we just generated, like \frac{6}{10} + \frac{\pi}{100}

We could just change that denominator a bit and get as many as we like.

But let's get some square roots.  The geometric mean will be between

\sqrt{ \dfrac 2 5 \cdot \dfrac 5 6 } = \dfrac{1}{\sqrt{3}}&#10;

That's the tangent from one of trig's biggest cliches, but I digress.  It's in between.

While we're on trig cliches, 

\dfrac{1}{\sqrt{2}}

is in between as well.

Keeping with the trig theme, also in between are

\dfrac{\pi} 6

and

\dfrac{\pi}{4}


the angles associated with the some of the above trig function values.

We could obviously go on as long as we cared to.



7 0
3 years ago
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