Ask question

Ask question

All categories

2 years ago

6

The math test has 10 multiple choice questions, each with 3 answers. If Betty guesses correctly on the first 3 questions, what i

s the probability that she will guess correctly on the fourth question?

2 answers:

Roman55 [17]2 years ago

5 0

I would say that Betty will have a probability to guess 1/3 on the fourth question due to the test only having 10 multiple choice questions with three answers.

alukav5142 [94]2 years ago

4 0

Answer: $\dfrac{1}{3}$

Step-by-step explanation:

Given: The number of multiple choices to each question = 3

We know that in multiple choice question there is only one answer is correct .

Then the probability that she will guess correctly on any question is given by :-

$=\dfrac{\text{Correct choice}}{\text{Total choices}}\\\\=\dfrac{1}{3}$

Hence, the the probability that she will guess correctly on the fourth question = $\dfrac{1}{3}$

You might be interested in

A 1350 kg car travels at 12 m/s. What is it's kinetic energy

qaws [65]

KE = 1/2(m * v^2)

KE = 1/2(1350 * 12^2)
KE = 1/2(1350 * 144)
KE = 1/2(194,400)
KE = 97,200 Joules

6 0

3 years ago

Read 2 more answers

What is the answer??

Lemur [1.5K]

Answer:

h(3) = - 140

Step-by-step explanation:

Generate the terms in the sequence by substituting n = 2 and 3 into h(n)

h(2) = h(2 - 1) × 2 = h(1) × 2 = - 35 × 2 = - 70

h(3) = h(3 - 1) × 2 = h(2) × 2 = - 70 × 2 = - 140

8 0

3 years ago

ln(y+1)-lny=1+3lnx . Express y in terms of x, in a form not involving logarithms. (4 marks, Maths CIE A level)

Delicious77 [7]

$remember$
$ln(x)=log_e(x)$
$and$
$log_x(a)-log_x(b)= log_x( \frac{a}{b} )$
$and$
$log_a(b)=c$ means $a^c=b$
$and$
$blog(a)=log(a^b)$

$so$

$ln(y+1)-ln(y)=1+3ln(x)$
$ln( \frac{y+1}{y} )=1+ln(x^3)$

$minus$ $ln(x^3)$ $from$ $both$ $sides$

$ln( \frac{y+1}{y}-ln(x^3) )=1$
$ln( \frac{y+1}{yx^3})=1$
$log_e( \frac{y+1}{yx^3})=1$

$translate$

$e^1=\frac{y+1}{yx^3}$
$e=\frac{y+1}{yx^3}$

$times$ $both$ $sides$ $by$ $yx^3$

$eyx^3=y+1$

$minus$ $y$ $from$ $both$ $sides$

$eyx^3-y=1$
$y(ex^3-1)=1$

$divide$ $both$ $sides$ $by$ $(ex³-1)$

$y= \frac{1}{ex^3-1}$

6 0

2 years ago

Read 2 more answers

Jim is fishing in a pond and there are 12 fish in the pond. 3 of the fish are trout and 9 are bass. If all of the fish are equal

Setler79 [48]

I think the answer id 1/22.

4 0

2 years ago

Read 2 more answers

An expression is given.

Katyanochek1 [597]

9514 1404 393

Answer:

34

Step-by-step explanation:

Maybe you want to evaluate ...

16 - 14 ÷ 2 + (3 +2)²

The parentheses are evaluated first.

16 -14÷2 +5²

Then the exponential term.

16 -14÷2 +25

The division is evaluated next.

16 -7 +25

Finally, the sum is evaluated.

= 9 +25

= 34

____

Your calculator can do this arithmetic for you.

5 0

3 years ago